The volume of the trough is V(w) = w³ + 20w² - 429w and the rate of change of the volume over a width of 38 inches to 53 inches is 4695 in³/in
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more variables and numbers.
Let w represent the width, hence:
length = w + 33, height = w - 13
Volume (V) = w(w + 33)(w - 13) = w³ + 20w² - 429w
V(w) = w³ + 20w² - 429w
Rate of change = dV/dw = 3w² + 40w - 429
When w = 38, dV/dw = 3(38)² + 40(38) - 429 = 5423
When w = 53, dV/dw = 3(53)² + 40(53) - 429 = 10118
Rate = 10118 - 5423 = 4695 in³/in
The volume of the trough is V(w) = w³ + 20w² - 429w and the rate of change of the volume over a width of 38 inches to 53 inches is 4695 in³/in
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160/3 is 53 1/3 as a fraction
Answer:c
Step-by-step explanation:
Given
and 
m of n is given by replacing x in 
by x-3
can take any value of x except x=4 because at x=4 function is not defined
and 
is also not defined for x=4 and can take any value of x
Answer:
x = (-5/2)
Step-by-step explanation:
4 - (2x + 4) = 5
-4 from both sides
- (2x + 4) = 1
divide both sides by -1
2x + 4 = -1
-4 from both sides
2x = -5
divide both sides by 2
x = (-5/2)
