Answer:
m = 44
Step-by-step explanation:
USe the pythagoream thyroem a^2 + b^2 = m^2. so 10^2 + m = 12^2
or 100 + m = 144. subtract 100 from both sides, you get m = 44
Answer:
5
Step-by-step explanation:
3x -12 = -36
-36 ÷ -3 = 12
-7 + 12 = 5
Answer:
In 1981, the Australian humpback whale population was 350
Po = Initial population = 350
rate of increase = 14% annually
P(t) = Po*(1.14)^t
P(t) = 350*(1.14)^t
Where
t = number of years that have passed since 1981
Year 2000
2000 - 1981 = 19 years
P(19) = 350*(1.14)^19
P(19) = 350*12.055
P(19) = 4219.49
P(19) ≈ 4219
Year 2018
2018 - 1981 = 37 years
P(37) = 350*(1.14)^37
P(37) = 350*127.4909
P(37) = 44621.84
P(37) ≈ 44622
There would be about 44622 humpback whales in the year 2018
Answer:
y=2
Step-by-step explanation:
1/3 (y+7) = 3(y-1)
Multiply each side by 3 to get rid of the fraction
3*1/3 (y+7) = 3*3(y-1)
y+7 = 9(y-1)
Distribute
y+7 = 9y - 9
Subtract y from each side
y+7-y = 9y-y-9
7 = 8y -9
Add 9 to each side
7+9 = 8y-9+9
16 = 8y
Divide each side by8
16/8 = 8y/8
2 = y
9514 1404 393
Answer:
increasing 7/24 ft per week
Step-by-step explanation:
An expression for the length of the base can be written from the Pythagorean theorem relation between the sides of the triangle.
If the height is 7-x, where x is the number of weeks after the height is 7 feet, then the base length is ...
b = √(25^2 -(7-x)^2) = √(625 -(49 -14x +x^2)) = √(-x^2 +14x +576)
Then the rate of change of b with respect to x is ...
b' = (-2x +14)/(2√(-x^2 +14x +576))
When x=0, the rate of change of the base is ...
b' = 14/(2√576) = 7/24
The base is increasing 7/24 ft per week when the height is 7 ft.
