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Anestetic [448]
2 years ago
10

An employee's gross pay for a period is $820. The employee takes one withholding for a state allowance of $19. There is also a s

tandard state deduction of $81. The state tax table says that if the amount of wages after subtracting withholding allowances and deductions is over $592 but not over $821, the amount of state income tax to withhold is 6.6% of the excess over $592 plus $16.06. What is the employee's state income tax withholding for the period?
A.$8.45
B.$63.58
C.$24.51
D.$47.52
Mathematics
1 answer:
kondor19780726 [428]2 years ago
4 0
I think the answer is D good luck
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what is the smallest number to be subtracted from 9610,so that the remainder will be a perfect square​
Romashka-Z-Leto [24]

Answer:

Hello,

Answer 6

Step-by-step explanation:

\sqrt{9610} =98,03060...\\\\ENT(\sqrt{9610})=98\\\\9610-98^2=9610-9604=6\\\\

The smallest number to be susbtracted is 6

4 0
2 years ago
In the circle, measure of Arc BC = 62°. The diagram isn't drawn to scale. what is the measure of Arc BCP?
bonufazy [111]
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3 years ago
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Yosef typed a 36 word paragraph in 2/3 minute. What is his typing speed, in words per minute?
Yakvenalex [24]

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2 years ago
Hippalectryon
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Since the stadium is 6 mi from the practice field which is itself 1 mi from the house, it can either be (1+6)=7 mi North or (1-6)=-5 -> 5 mi South depending on the North/South direction.

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2 years ago
A map is laid out in the standard (x,y) coordinate plane. How long, in units, is an airplane's path on the map as the airplane f
xeze [42]

Answer:

Distance between the points A and B is 15.52 units.

Step-by-step explanation:

It has been given in the question that an airplane flies along a straight line from City A to City B.

Map has been laid out in the (x, y) coordinate plane and the coordinates of these cities are A(20, 14) and B(5, 10).

Distance between two points A'(x, y) and B'(x', y') is represented by the formula,

d = \sqrt{(x-x')^{2}+(y-y')^{2}}

So we plug in the values of (x, y) and (x', y') in the formula,

d = \sqrt{(20-5)^{2}+(14-10)^{2}}

d = \sqrt{(15)^{2}+(4)^{2}}

d = \sqrt{225+16}

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Therefore, distance between the points A and B is 15.52 units.

4 0
3 years ago
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