Answer:
y = 6.5 units
Step-by-step explanation:
Let L be the length of sides of the square.
Given the following data;
Perimeter of square = 8y - 12
Area of square = 100 square units
To find the value of y;
Area of a square = L²
Substituting into the formula, we have;
100 = L²
L = √100
L = 10 units
Mathematically, the perimeter of a square is given by the formula;
Perimeter of a square = 4L
Substituting into the formula, we have;
8y - 12 = 4*10
8y - 12 = 40
8y = 40 + 12
8y = 52
y = 52/8
y = 6.5 units
Tahmid has 96 figures, Sandeep has 1/3 of it so
96(1/3) = 96/3 = 32
Sandeep has 32 figures
Tahmid 96 ; Sandeep 32
How many must tahmid give so they have the same figures?
First take the difference of the two so we know how many tahmid can give.
96-32 = 64
now they each have 32 and 64 give or keep. for each one tahmid gives, he must keep one himself so to match the number they both own. so we divide the number of 2, one part to give, the other part to keep himself.
64/2 = 32
So, Tahmid must give Sandeep 32 figures to have equal number of figures of 64 each.
Let the first number be = x
Then the second number = 2x
The third number = 2x - 5
Their sum = 55
This can be written in an equation as =
x + 2x + 2x - 5 = 55
= x + 2x + 2x = 55 + 5 ( transposing -5 from LHS to RHS changes -5 to +5 )
= x + 2x + 2x = 60
= 5x = 60
= x = 60 ÷ 5 ( transposing ×5 from LHS to RHS changes ×5 to ÷5 )
= x = 12
The first number = x = 12
The second number = 2x = 2 × 20 = 24
The third number = 2x - 5 = 24 - 5 = 19
Therefore , the three numbers are 12 , 24 and 19 .
Answer:
No solution
Step-by-step explanation:
Unfortunately your screenshot has cut off the final answer choice, if it says "no solution" you should choose that because these two lines are parallel. Meaning they will never intersect, and the point of intersection is usually the solution.
I think it’s 3 times because 2*3=6 and 4*3=12 and 6*3=18
