I got C for 6 & 7. I haven't done this in a while so I don't know 8 & 9. I hope I helped!
Answer:
d. interquartile range
Step-by-step explanation:
the iqr measures the first, second, and third quartile, and the median.
Let V, be the rate in still water and let C = rate river current
If the boat is going :
upstream, its rate is V-C and if going
downstream, its rate is V+C,
But V = 5C, then
Upstream Rate: 5C - C = 4 C
Downstream rate: 5C+C = 6C
Time = distance/Rate, (or time = distance/speed) , then:
Upstream time 12/4C and
Downstream time: 12/.6C
Upstream time +downstream time:= 2h30 ' then:
12/4C + 12/.6C = 2.5 hours
3/C + 2/C = 5/2 (2.5 h = 5/2)
Reduce to same denominator :
5C = 10 and Rate of the current = 2 mi/h
1+3x /4= 5/2
1+3x = 5*4/2
1+3x =10
3x =9
x = 3
. What are the lower, middle, and upper quartiles of this data? 23, 15, 22, 15, 23, 15, 13, 21, 14 a. lower: 15, middle: 15, upp
icang [17]
The correct answer us D. lower: 14.5 middle: 15 upper: 22.5
