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Jobisdone [24]
3 years ago
7

For parallelogram PQRS, PT=2x-1, QT=x+4RT = y 1, and ST - 3y - 11.

Mathematics
1 answer:
olganol [36]3 years ago
7 0
R IS THE ANSWERRRRR!!!
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Which phrase best defines erosion a) chemically breaking rocks apart b) physically breaking rocks apart c) moving bits of rock f
Eddi Din [679]

Answer:

C) moving bits of rock from place to place

Step-by-step explanation:

A is chemical weathering, b is mechanical weathering, and d is cementation

5 0
3 years ago
Find the value of x
Bess [88]

Step-by-step explanation:

the answer is

2x+4x =90

6x=90

x=15°

3 0
3 years ago
HEEELP ME GEOMETRY HW #29 AND #30 I'VE BEEN STUCK ON IT FOR HOURS!!!!!
natulia [17]
On #29 x = 12 and <apb = 90° and <dcb = 40° and on #30 all I dont even understand, sorry
5 0
4 years ago
Leila works as a tutor for an hour and as a waitress for an hour. This month, she worked a combined total of hours at her two jo
kupik [55]

Answer:

E(t)  =  5t +672     ($)

Step-by-step explanation:     INCOMPLETE QUESTION

FROM GOOGLE

she earns 12 $ per hour as tutor and 7 $ per hour as waitress, this month she worked a combined of 96 hours at her two jobs

Let be t the numbers of hours Leila works as tutor this month

Answer:

If Leila worked t hours as tutor then, she worked (96 - t) hours as waitress

E(t)  =  12 * t  +  7 * (96-t)

E(t)  =  12t   +  672 - 7t

E(t)  =  5t +672     ($)

7 0
3 years ago
How do you verify this trigonometric identity? cos^2 θcot^2 θ = cot^2 θ - cos^2 θ
sattari [20]
<h3>Explanation:</h3>

Replace cos^2(θ) with 1-sin^2(θ), and cot(θ) with cos(θ)/sin(θ).

  cos^2(θ)cot^2(θ) = cot^2(θ) - cos^2(θ)

  (1 -sin^2(θ))cot^2(θ) =  . . . . . replace cos^2 with 1-sin^2

  cot^2(θ) -sin^2(θ)·cos^2(θ)/sin^2(θ) = . . . . . replace cot with cos/sin

  cot^2(θ) -cos^2(θ) = cot^2(θ) -cos^2(θ) . . . as desired

8 0
3 years ago
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