Answer:
Explanation:
The table that shows the pattern for this question is:
Time (year) Population
0 40
1 62
2 96
3 149
4 231
A growing exponentially pattern may be modeled by a function of the form P(x) = P₀(r)ˣ.
Where P₀ represents the initial population (year = 0), r represents the multiplicative growing rate, and P(x0 represents the population at the year x.
Thus you must find both P₀ and r.
<u>1) P₀ </u>
Using the first term of the sequence (0, 40) you get:
P(0) = 40 = P₀ (r)⁰ = P₀ (1) = P₀
Then, P₀ = 40
<u> 2) r</u>
Take two consecutive terms of the sequence:
- P(1) / P(0) = 40r / 40 = 62/40
You can verify that, for any other two consecutive terms you get the same result: 96/62 ≈ 149/96 ≈ 231/149 ≈ 1.55
<u>3) Model</u>
Thus, your model is P(x) = 40(1.55)ˣ
<u> 4) Population of moose after 12 years</u>
- P(12) = 40 (1.55)¹² ≈ 7,692.019 ≈ 7,692, which is round to the nearest whole number.
Answer:
f(-3)= -3
Step-by-step explanation:
We are given the function:
f(x) = 2x+3
and asked to find f(-3). Essentially, we want to find f(x) when x is equal to -3.
Therefore, we can substitute -3 for each x in the function.
f(x)= 2x+3 at x= -3
f(-3)= 2(-3) +3
Solve according to PEMDAS: Parentheses, Exponents, Multiplication, Division, Addition and Subtraction
Multiply 2 and -3.
f(-3) = (2*-3) +3
f(-3)= (-6)+3
Add -6 and 3.
f(-3)= (-6+3)
f(-3)= -3
If f(x)= 2x+3, then<em> f(-3)= -3</em>
Hello there.
<span>Least to greatest 7/12,0.75,5/6
7/12 ,5/6, 0.75</span>
I think it's B because it's makes the most sense
The answer to your problem is A 1/3, is the possibility for a passenger who arrives at noon.
