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Ira Lisetskai [31]
3 years ago
12

What is the constant in this expression? m-4n+3.5+4/5p

Mathematics
2 answers:
Komok [63]3 years ago
6 0

3.5 is the constant. A constant is a term that only consists of a number and doesn't have any variable next to it, basically a number that stands by itself. In this case 3.5 is the only constant, lone number, in the equation, so 3.5 would be the answer.

If you liked my answer, make sure to leave a Brainliest (:

Lisa [10]3 years ago
5 0

Answer:

3.5

Step-by-step explanation:

We are given that an expression

m-4n+3.5+\frac{4}{5}p

We have to find the constant in the given expression

Constant:That number which is numerical number and do not change remain same.

Variable : That number which is represented by letter x, y  etc and varying and do not remain  same.

In the given expression 3.5 is constant because 3.5  is fixed and do not change.

Hence, 3.5 is  constant.

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Expand and simplify (2x+2)(2x+1)
s344n2d4d5 [400]

Answer:

4x^2+6x+2

Step-by-step explanation:

8 0
3 years ago
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PART A: how many miles per gallon does the car get
Nastasia [14]
Part a: 30 gallons (i think)


part b: 220
3 0
3 years ago
A cat gave birth to 3333 kittens who each had a different mass between 147147147147 and 159 g159\,\text{g}159g159, start text, g
harina [27]

Answer:

The correct option is (B).

Step-by-step explanation:

The median (m) is a measure of central tendency. To obtain the median, we assemble the data in arising order. If the data is odd, the median is the mid-value. If the data is even, the median is the arithmetic-mean of the two mid-values.

The mean of a data set is:

\bar X=\frac{1}{n}\sum\limits^{n}_{x=0}{X}

For the three kittens it is provided that the weights are in the range 147 g to 159 g.

So, the mean and median weight for the 3 kittens lies in the middle of this range.

Now a fourth kitten is born, with weight 57 g.

Now the range of the weight of 4 kittens is, 57 g to 159 g.

The mean is going to decrease as one more value is added to the data and the value is the least.

The median will also decrease because now the median will be mean of the 2nd and 3rd values.

But the mean would decrease more than the median because a smaller value is added to the data.

Thus, the correct option is (B).

5 0
3 years ago
Is 1.61 kilometers a foot
Alex73 [517]

No, it's a little more than that.

1.61 kilometers is  5,282.2 feet.

That's about  2.2 feet longer than 1 mile.

6 0
3 years ago
The area of a rectangle is 21 yd.² and the length of a rectangle is 1 yard or less than twice the width find the dimensions of t
emmasim [6.3K]

Answer:

length = 6 yards

width = 3.5 yards

Step-by-step explanation:

the length of a rectangle is 1 yard less than twice the width

LEt 'w' be the width of the rectangle

and 'l' be the length of the rectangle

length l = 2 times the width -1

so l = 2w -1

Area of the rectangle = length * width

Area = l * w

we know length is 2w-1  and given area = 21

21 = (2w-1) * w

21= 2w^2 - w

subtract 21 on both sides

0= 2w^2 - w - 21

now solve for 'w'

0= 2w^2 +6w -7w- 21

0 = 2w(w+3)-7(w+3)

0= (2w-7)(w+3)

2w-7 = 0                    and w+3 =0

w = 7/2                            w=-3

width cannot be negative so we ignore w=-3

width w= 3.5

length = 2w-1= 2(3.5) - 1= 7-1=6

length = 6 yards

5 0
3 years ago
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