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Vinvika [58]
3 years ago
10

Can someone help me out pls i’ll give brainliest!

Mathematics
1 answer:
iragen [17]3 years ago
6 0

answer

three

explain hope this helps

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It is given that m=3x+1 and y= (5/1+m^2).<br>Find dy/dx in terms of x.<br>​
DiKsa [7]

Answer:

{ \underline{ \bf{ \frac{dy}{dx}  =  -  \frac{30m}{ {(1 +  {m}^{2}) }^{2} } }}}

Step-by-step explanation:

{ \bf{m = 3x + 1}} \\ { \sf{ \frac{dm}{dx} = 3 }} \\  \\ { \bf{y =  \frac{5}{1 +  {m}^{2} } }} \\ \\  { \tt{ \frac{dy}{dm} =  \frac{ - 10m}{ {(1 +  {m}^{2} )}^{2} }  }}

Using chain rule:

{ \boxed{ \bf{ \frac{dy}{dx}  =  \frac{dy}{dm}. \frac{dm}{dx}  }}}

{ \sf{ \frac{dy}{dx}  =  -  \frac{10m}{ {(1 +  {m}^{2}) }^{2} }  \times 3}} \\  \\ { \sf{ \frac{dy}{dx}  =  -  \frac{30m}{ {(1 +  {m}^{2}) }^{2} } }}

{ \underline{ \sf{ \blue{christ \:† \: alone }}}}

8 0
3 years ago
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Geometry help!! ASAP!
Julli [10]
Cos x = adj/hyp

Cos F = 6/10 = 3/5


Answer: 3/5
4 0
3 years ago
At the city museumy child admission is and admission is $9.30. On Monday four times as many adult tickets as child tickets were
Scilla [17]

<em><u>Question:</u></em>

At the city museum, child admission is $5.80 and adult admission is $9.30. On Monday, four times as many adult tickets as child tickets were sold, for a total sales of $1548.00. How many child tickets were sold that day?

<em><u>Answer:</u></em>

36 child tickets were sold

<em><u>Solution:</u></em>

Given that,

Cost of 1 child admission = $ 5.80

Cost of 1 adult admission = $ 9.30

Let "c" be the number of child tickets sold

Let "a" be the number of adult tickets sold

On Monday, four times as many adult tickets as child tickets were sold

Number of adult tickets sold = four times the number of child tickets

Number of adult tickets sold = 4(number of child tickets sold)

a = 4c ----- eq 1

They were sold for a total sales of $ 1548.00

number of child tickets sold x Cost of 1 child admission + number of adult tickets sold x Cost of 1 adult admission = 1548.00

c \times 5.80 + a \times 9.30 = 1548

5.8c + 9.3a = 1548  ---- eqn 2

Let us solve eqn 1 and eqn 2 to find values of "c" and "a"

Substitute eqn 1 in eqn 2

5.8c + 9.3(4c) = 1548

5.8c + 37.2c = 1548

43c = 1548

c = 36

Thus 36 child tickets were sold that day

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4 years ago
What is the place value of 2.025
TEA [102]

Answer:

This is my answer !

Step-by-step explanation:

2 ones 2 hundredths and 5 thousandth

8 0
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Evelyn has a bag containing red (R), blue (B), and green (G) marbles as shown below. If each marble is replaced after it is draw
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the probability of drawing three consecutive red marbles is based on how many red marbles you have and many marble there is in total.

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