Can someone help me out pls i’ll give brainliest!

Find the area of a rhombus with a perimeter equal to 40 and a diagonal equal to 14 cm.

krek1111 [17]

Answer:

about 100 cm²

Step-by-step explanation:

The side length of the rhombus is 1/4 of the perimeter so is 10 cm. The length of half of the other diagonal will be the length of the leg of a right triangle with hypotenuse 10 and leg 7 (half the given diagonal).

d= √(10² -7²) = √51

Then the area of the rhombus is the product of this and the given diagonal:

A = (14 cm)(√51 cm) ≈ 99.98 cm²

The area of the rhombus is about 100 cm².

6 0

4 years ago

I need help REALLY FAST what is the distance between the points (-1, -3 3/4) and (-1, 4 1/2) ?

kodGreya [7K]

Answer:

8 1/4

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Coordinates (x, y)

Algebra II

Distance Formula: $\displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Step-by-step explanation:

Step 1: Define

Identify

Point (-1, -3.75)

Point (-1, 4.5)

Step 2: Find distance d

Simply plug in the 2 coordinates into the distance formula to find distance d

Substitute in points [Distance Formula]: $\displaystyle d = \sqrt{(-1--1)^2+(4.5--3.75)^2}$
[√Radical] (Parenthesis) Subtract: $\displaystyle d = \sqrt{(0)^2+(8.25)^2}$
[√Radical] Evaluate exponents: $\displaystyle d = \sqrt{0+68.0625}$
[√Radical] Add: $\displaystyle d = \sqrt{68.0625}$
[√Radical] Evaluate: $\displaystyle d = 8.25$