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Pavel [41]
2 years ago
15

Solve the following:

Mathematics
2 answers:
GrogVix [38]2 years ago
7 0
The answer you are looking for is 2& 3/10
arlik [135]2 years ago
4 0
2 3/10
5 1/10 - 2 8/10
You can’t subtract 1/10 by 8/10 so you regroup
The 5 turns into a 4 and 1/10 turns into 11/10
New equation would be 4 11/10 - 2 8/10 = 2 3/10
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A piece of wire of length 7070 is​ cut, and the resulting two pieces are formed to make a circle and a square. Where should the
lyudmila [28]

Answer:

a.x=39.2

b.Use whole  wire as a circle

Step-by-step explanation:

We are given that

Length of piece of wire=70  units

Let length of wire used to make a square =x units

Length of wire used in circle=70- x

Side of square=\frac{perimeter\;of\;square}{4}=\frac{x}{4}

Circumference of circle=2\pi r

70-x=2\pi r

r=\frac{70-x}{2\pi}

Combined area of circle and square,A=(\frac{x}{4})^2+\pi(\frac{70-x}{2\pi})^2

Using the formula

Area of circle=\pi r^2

Area of square=(side)^2

a.A=\frac{x^2}{16}+\frac{4900+x^2-140x}{4\pi}

Differentiate w.r.t x

\frac{dA}{dx}=\frac{x}{8}+\frac{2x-140}{4\pi}

\frac{dA}{dx}=0

\frac{x}{8}+\frac{2x-140}{4\pi}=0

\frac{\pi x+4x-280}{4\pi}=0

\pi x+4x-280=0

x(\pi+4)=280

x=\frac{280}{\pi+4}

x=39.2

Again differentiate w.r.t x

\frac{d^2A}{dx^2}=\frac{1}{8}+\frac{1}{2\pi}>0

Hence, the combined area of circle and the square is minimum at x=39.2

b.When the wire is not cut and whole wire used  as a circle . Then, combined area is maximum.

3 0
3 years ago
what is the opportunity cost of buying a $.75 soda every school day for three years instead of drinking water? assume you are in
11Alexandr11 [23.1K]

Answer:

I don't understand your question

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3 years ago
Lught herzu <br><img src="https://tex.z-dn.net/?f=%20%7Bx%7D%5E%20%7B2%7D%20%20-%20xy%20%2B%20%20%7Bx%7D%5E%7B2%7D%20%20%20-%20x
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Answer:

sry I can't understand how to do this question

3 0
2 years ago
Read 2 more answers
Find the slope of the line through the given points.<br> (8,0) and (10, 10)
postnew [5]
Slope (y2-y1)/(x2-x1)
(10-0)/(10-8) = 10/2 = 5
The slope is 5
6 0
2 years ago
Why is 25 mg lighter than 25 cg
Mashutka [201]
25 mg is lighter than 25 cg because mg is 0.001 g and cg is 0.01 g :)
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2 years ago
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