I think the first one or the thrid one
hope this help
Answer:
Test statistic = 1.664
Step-by-step explanation:
The hypothesis :
H0 : μ = 47.2
H1 : μ ≠ 47.2
Given that :
Sample mean, xbar = 47
Sample size, n = 250
Standard deviation, σ = 1.9
The test statistic :
(xbar - μ) ÷ (σ/√(n))
T = (47 - 47.2) ÷ (1.9/√(250))
T = (0.2 / 0.1201665)
Test statistic = 1.664
Answer:
252=252 so
Step-by-step explanation:
Answer:
Step-by-step explanation:
For this case we have the following numbers:
624
27
When dividing both numbers, we observe that:
The partial quotient of the division is equal to 23
The rest of the division is equal to 3.
Note: See attached image to see the procedure of the division between both numbers.
Answer:
the partial quotient of 624 divided by 27 is:
23
Answer:
88
Step-by-step explanation:
Write the expression for the sum in the relation you want.
Sn = u1(r^n -1)/(r -1) = 2.1(1.06^n -1)/(1.06 -1)
Sn = (2.1/0.06)(1.06^n -1) = 35(1.06^n -1)
The relation we want is ...
Sn > 5543
35(1.06^n -1) > 5543 . . . . substitute for Sn
1.06^n -1 > 5543/35 . . . . divide by 35
1.06^n > 5578/35 . . . . . . add 1
n·log(1.06) > log(5578/35) . . . take the log
n > 87.03 . . . . . . . . . . . . . . divide by the coefficient of n
The least value of n such that Sn > 5543 is 88.
