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3 years ago

Find the area of a rectangle that is 4-inches-wide and 15-inches-long.

Mathematics

2 answers:

Ratling [72]3 years ago

3 0

Answer:

the area of a rectangle that is 4-inches-wide and 15-inches-long =15*4=<u>60 </u><u>square</u><u> </u><u>inches</u>

andreev551 [17]3 years ago

3 0

Width=4in
Length=15in

$\\ \sf\longmapsto Area=Length\times width$

$\\ \sf\longmapsto Area=4(15)$

$\\ \sf\longmapsto Area=60in^2$

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which of the following equations is the equation of a suitable line of best fit for the data given below {(45,18), (62,13), (72,

Nuetrik [128]

Sort the data by x:

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3 years ago

Solve quadratic inequality x^2+4x≥0

klemol [59]

Answer:

Step-by-step explanation:

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2 years ago

A standard letter-sized piece of paper has a length and width of 8.5 inches by 11 inches.

den301095 [7]

Answer:

Area of the resulting rectangle = 23.375 inch²

Step-by-step explanation:

After 1 fold width or length reduces to half.

Area = Length x width

So after 1 fold area will reduce to half.

So we have

$\texttt{Area after n folds =}\frac{\texttt{Initial area}}{2^{\texttt{number of folds}}}$

Initial area = 8.5 x 11 = 93.5 inch²

Here the paper were folded completely in half, length is reduced to half and width reduced to half, that is

Number of folds = 2

$\texttt{Area after 2 folds =}\frac{\texttt{Initial area}}{2^{2}}\\\\\texttt{Area after 2 folds =}\frac{93.5}{4}=23.375inch^2$

Area after 2 folds = 23.375 inch²

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3 years ago

Help me plz, thanks.

chubhunter [2.5K]

6/20 chance or simplified would be 3/10. Answer [D] is correct.

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3 years ago

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Triangle XYZ is translated 4 units up and 3 units left to yield ΔXYZ. What is the distance between any two corresponding points

Mashcka [7]

<h3>Answer:</h3>

5 units

<h3>Step-by-step explanation:</h3>

A point 4 up and 3 over from its original location has moved a distance that can be found using the Pythagorean theorem.

... d² = 4² +3² = 16 +9 = 25

... d = √25 = 5 . . . . units

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3 years ago

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