Answer: A.
Step-by-step explanation:
Answer:
6 liters
Step-by-step explanation:
Let x represent the amount of pure concentrate used to make the punch. Then the total amount of concentrate in the punch is ...
0.20·10 +1.00x = 0.50(10+x)
x +2 = 0.5x +5 . . . . . eliminate parentheses
0.5x = 3 . . . . . . . . . . .subtract 2+0.5x
x = 6 . . . . . . . . . . . . . multiply by 2
6 liters of pure concentrate must be added to make a 50% punch.
Answer:
Step-by-step explanation:
(6u)+(-2u)=4u
(-7c)+(4c)=-3c
6=6
4u-3c+6
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Hi my lil bunny!
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Lets do this step by step.
This is the trigonometric form of a complex number where
is the modulus and
is the angle created on the complex plane.
![z = a + bi = |z| (cos ( 0 ) + I sin (0))](https://tex.z-dn.net/?f=z%20%3D%20a%20%2B%20bi%20%3D%20%7Cz%7C%20%28cos%20%28%200%20%29%20%2B%20I%20sin%20%280%29%29)
The modulus of a complex number is the distance from the origin on the complex plane.
where ![z = a + bi](https://tex.z-dn.net/?f=z%20%3D%20a%20%2B%20bi)
Substitute the actual values of a = -5 and b = -5.
![|z| = \sqrt{(-5) ^2 + (-5) ^2}](https://tex.z-dn.net/?f=%7Cz%7C%20%3D%20%5Csqrt%7B%28-5%29%20%5E2%20%2B%20%28-5%29%20%5E2%7D)
Now Find
.
Raise - 5 to the power of 2.
![|z| = \sqrt{25 + (-5) ^2}](https://tex.z-dn.net/?f=%7Cz%7C%20%3D%20%5Csqrt%7B25%20%2B%20%28-5%29%20%5E2%7D)
Raise - 5 to the power of 2.
![|z| = \sqrt{25 + 25}](https://tex.z-dn.net/?f=%7Cz%7C%20%3D%20%5Csqrt%7B25%20%2B%2025%7D)
Add 25 and 25.
![|z| = \sqrt{50}](https://tex.z-dn.net/?f=%7Cz%7C%20%3D%20%5Csqrt%7B50%7D)
Rewrite 50 as 5^2 . 2 .
![|z| = 5\sqrt{2}](https://tex.z-dn.net/?f=%7Cz%7C%20%3D%205%5Csqrt%7B2%7D)
Pull terms out from under the radical.
![|z| = 5\sqrt{2}](https://tex.z-dn.net/?f=%7Cz%7C%20%3D%205%5Csqrt%7B2%7D)
The angle of the point on the complex plane is the inverse tangent of the complex portion over the real portion.
![0 = arctan (\frac{-5}{-5} )](https://tex.z-dn.net/?f=0%20%3D%20arctan%20%28%5Cfrac%7B-5%7D%7B-5%7D%20%29)
Since inverse tangent of
produces an angle in the third quadrant, the value of the angle is
.
![0 = \frac{5\pi }{4}](https://tex.z-dn.net/?f=0%20%3D%20%5Cfrac%7B5%5Cpi%20%7D%7B4%7D)
Substitute the values of
and
.
![5\sqrt{2} ( cos( \frac{5\pi}{4}) + i sin (\frac{5\pi}{4}))](https://tex.z-dn.net/?f=5%5Csqrt%7B2%7D%20%28%20cos%28%20%5Cfrac%7B5%5Cpi%7D%7B4%7D%29%20%20%2B%20i%20sin%20%28%5Cfrac%7B5%5Cpi%7D%7B4%7D%29%29)
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Hope this helped you.
Could you maybe give brainliest..?
❀*May*❀
Given P is T, q is F and r is F.
Let us find p ↔ q first.
↔ is called bi-conditional operator and is true when p and q both are matched.
Since here p is T and q is F, p↔q is F. ( Since p and q are not matching)
~p v r = ~T v F = F v F = F
Hence (p↔q)→(~pvr) = F → F = T (Since conditional operator → is false if and if first proposition is T and second proposition is F, for all other values it is T)