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Alina [70]
2 years ago
10

Plz help this is due today NO LINKS OR GROSS PICTURES OR I Will REPORT And please show work

Mathematics
1 answer:
aniked [119]2 years ago
8 0

Answer:

2280 the volume

Step-by-step explanation:

So one box = 480

So then what about 6 boxes?

you do 480 x 6 =   2880

480+ 480+ 480+ 480+480+480= 2880

You might be interested in
An insurance company has 25,000 automobile policy holders. If the yearly claim of a policy holder is a random variable with mean
telo118 [61]

Answer:

P(T>8300000)=1-P(T

Step-by-step explanation:

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Data given

n = 25000 represent the automobile policy holders

\mu= 320 represent the population mean

\sigma =540 represent the population standard deviation

Let T the variable that represent the total of interest on this case. We can assume that the random variable for an individual policy holder is given by:

X\sim N(\mu = 540, \sigma=540)

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

Solution to the problem

First we need to find the distribution for the random variable T like this:

\bar X = \frac{\sum_{i=1}^n x_i}{n}

And the total T is given by:

T=\sum_{i=1}^n X_i =n \bar X

We can find the expected value, variance and deviation for this random variable like this:

E(T)= n E(\bar X) = n \mu = 25000*320=8000000

Var(T)= Var(n\bar X)= n^2 Var(\bar X) = n^2 \frac{\sigma^2}{n}=n \sigma^2 =25000*(540^2)=7290000000

Sd(T)=\sqrt{7290000000}=85381.497

And we are interested on this probability:

P(T>8300000)

And we can use the Z score formula given by:

Z=\frac{T-E(T)}{\sigma_T}

P(T>8300000)=1-P(T

6 0
3 years ago
If you roll two fair six-sided dice, what is the probability that both dice show an odd number?
OLEGan [10]

Answer:

1/4

Step-by-step explanation:

Both dice have odd numbers 1, 3, 5. The chances of getting an odd number on each number is 3/6

The probability of getting odd numbers on both is:

3/6 ⋅ 3/6 = 9/36 = 1/4

5 0
3 years ago
Read 2 more answers
hakeem's frog made 3 quick jumps. the first was 1m. the second was 85cm and the third was 400mm. what was the total length in cm
azamat
1m=100cm
85 cm
400 mm=40 cm
Add up them up and you get 225 cm in total
4 0
3 years ago
Country A has a population of 514,482 and Country B has a population of 523,407. How would you compare these populations
prohojiy [21]
You can subtract the populations to see by how many more people/citizens does country B have
8 0
3 years ago
What is 6 divided by 1,932
yawa3891 [41]

Step-by-step explanation:

do u mean 1,932 divided by six?

8 0
3 years ago
Read 2 more answers
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