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3 years ago

10

Write an equation for the line, in point-slope form, that passes through the following point and has the following slope:slope:-

4 point: (1, -2)

1 answer:

enyata [817]3 years ago

5 0

Answer:

y+2=-4(x-1)

Step-by-step explanation:

y-y1=slope(x-x1)

just plug in the numbers you were given and youre good to go

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How do you get 6,300,00 using the digits 1-7 to creat a seven-digit number that can be rounded to 6,300,000?

Tomtit [17]

In the problem, how do you get 6,300,000 using the digits 1-7 to create a seven-digit number that can be rounded to 6,300,000. We can use the numbers according to the rule of rounding values, 0-4 and 5-9. Hence the numbers are:
1. 6, 290,000 = 6, 300, 000
2. 6, 310, 000 = 6, 300, 000 Therefore the numbers concerned in the given value is in the place order of ten thousand which will determine the hundred thousands’ value.

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3 years ago

Suppose we play the following game based on tosses of a fair coin. You pay me $10, and I agree to pay you $n 2 if heads comes up

Artyom0805 [142]

Answer:

In the long run, ou expect to lose $4 per game

Step-by-step explanation:

Suppose we play the following game based on tosses of a fair coin. You pay me $10, and I agree to pay you $n^2 if heads comes up first on the nth toss.

Assuming X be the toss on which the first head appears.

then the geometric distribution of X is:

X $\sim$ geom(p = 1/2)

the probability function P can be computed as:

$P (X = n) = p(1-p)^{n-1}$

where

n = 1,2,3 ...

If I agree to pay you $n^2 if heads comes up first on the nth toss.

this implies that , you need to be paid $\sum \limits ^{n}_{i=1} n^2 P(X=n)$

$\sum \limits ^{n}_{i=1} n^2 P(X=n) = E(X^2)$

$\sum \limits ^{n}_{i=1} n^2 P(X=n) =Var (X) + [E(X)]^2$

$\sum \limits ^{n}_{i=1} n^2 P(X=n) = \dfrac{1-p}{p^2}+(\dfrac{1}{p})^2$ ∵ X $\sim$ geom(p = 1/2)

$\sum \limits ^{n}_{i=1} n^2 P(X=n) = \dfrac{1-p}{p^2}+\dfrac{1}{p^2}$

$\sum \limits ^{n}_{i=1} n^2 P(X=n) = \dfrac{1-p+1}{p^2}$

$\sum \limits ^{n}_{i=1} n^2 P(X=n) = \dfrac{2-p}{p^2}$

$\sum \limits ^{n}_{i=1} n^2 P(X=n) = \dfrac{2-\dfrac{1}{2}}{(\dfrac{1}{2})^2}$

$\sum \limits ^{n}_{i=1} n^2 P(X=n) =\dfrac{ \dfrac{4-1}{2} }{{\dfrac{1}{4}}}$

$\sum \limits ^{n}_{i=1} n^2 P(X=n) =\dfrac{ \dfrac{3}{2} }{{\dfrac{1}{4}}}$

$\sum \limits ^{n}_{i=1} n^2 P(X=n) =\dfrac{ 1.5}{{0.25}}$

$\sum \limits ^{n}_{i=1} n^2 P(X=n) =6$

Given that during the game play, You pay me $10 , the calculated expected loss = $10 - $6

= $4

∴

In the long run, you expect to lose $4 per game

3 0

3 years ago

Why should people conserve energy? (Please don’t get the answer form the internet)

Taya2010 [7]

People should conserve energy because it produces a higher quality of life. Reduced emissions result in cleaner air quality. It also helps create a healthier planet and helps sustain resources we have.

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2 years ago

6. There are four-wheel trucks and six-

Nat2105 [25]

Answer:

there are 6 six wheel trucks

Step-by-step explanation:

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3 years ago

W is greater than -5 and less than 0

Ronch [10]

Yessndndndd dndndndndndndndndndd

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3 years ago