Answer:
B. 1/9 cuz it's just saying y is 1/9 of x
Answer:
<u>i think</u> it is 40%
Step-by-step explanation:
she made 2/5 shots so
2/5*2=4/10
i times it by 2 because its out of 100
4/10*10=40/100
then i times it by 10 to get to 100
(2/5 is not 2 divided by five it is 2 over 5 just incase u didnt know what i was talking about)
Answer:
- attached graph
- Horizontal Asymptote: y = 5
- twon whole number points are (4,4) and (5,1)
Step-by-step explanation:
- Exponential functions have a horizontal asymptote. The equation of the horizontal asymptote
y = -4^(x-4) + 5
= -4^(4-4) + 5
= -4^(0) + 5
= -1 + 5
= 4
y = -4^(x-4) + 5
= -4^(5-4) + 5
= -4^(1) + 5
= -4 + 5
= 1
Answer:
Step-by-step explanation:

Use the order of operations.
Note: PEMDAS or BODMAS stands for:
<u>PEMDAS</u>
- <u>Parentheses</u>
- <u>Exponents</u>
- <u>Multiply</u>
- <u>Divide</u>
- <u>Add</u>
- <u>Subtract</u>
<u>BODMAS</u>
- <u>Brackets</u>
- <u>Order</u>
- <u>Divide</u>
- <u>Add</u>
- <u>Subtract</u>
<u>First, do parentheses.</u>
3+6*(5+4)÷3-7
(5+4)=9

<u>Do multiply and divide.</u>
6*9=54
54/3=18
<u>Then, rewrite the problem down.</u>

<u>Add.</u>



- <u>Therefore, the correct answer is "C. 14".</u>
I hope this helps, let me know if you have any questions.