The nearest tenth of how fast a rover will hit Mars' surface after a bounce of 15 ft in height is 20.7ft/s.
<h3>What is the approximation about?</h3>
From the question:
Mars: F(x) = 2/3
Therefore, If x = 15
Then:
f (15) = 2/3 ![\sqrt[8]{15}](https://tex.z-dn.net/?f=%5Csqrt%5B8%5D%7B15%7D)
= 16/3
= 20.7ft/s
Hence, The nearest tenth of how fast a rover will hit Mars' surface after a bounce of 15 ft in height is 20.7ft/s.
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Change any number of feet to inches. Every foot is equal to 12 inches. So multiply the number of feet you have by 12.
Ex. 5 feet= 60inches
Answer: Pretty Simple; an easy equation could be 10 + 4 = 14.
Step-by-step explanation:
A more difficult equation might be (10(8) - 70) + 4 = 14
:)
Answer:
2x⋅(7x2−3x+6y 2 )
Step-by-step explanation: