(use a proportion) what is 128% of 550?

Mathematics

1 answer:

Katen [24]4 years ago

4 0

Answer:

704

Step-by-step explanation:

1. We assume, that the number 550 is 100% - because it's the output value of the task.

2. We assume, that x is the value we are looking for.

3. If 550 is 100%, so we can write it down as 550=100%.

4. We know, that x is 128% of the output value, so we can write it down as x=128%.

5. Now we have two simple equations:

1) 550=100%

2) x=128%

where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:

550/x=100%/128%

6. Now we just have to solve the simple equation, and we will get the solution we are looking for.

7. Solution for what is 128% of 550

550/x=100/128

(550/x)*x=(100/128)*x - we multiply both sides of the equation by x

550=0.78125*x - we divide both sides of the equation by (0.78125) to get x

550/0.78125=x

704=x

x=704

now we have:

128% of 550=704

You might be interested in

How many positive four-digit integers have the three digits the same and a different fourth digit (in some order)

malfutka [58]

Answer:

81 * 4 = 324.

Step-by-step explanation:

There are 81 * 4 = 324 such integers.

There are 9000 four-digit integers from 1000 to 9999. Let’s refer to the digit that occurs three times as the triplet and the digit that occurs once as the singleton.

In the first (most significant) position there are 9 possible values for the singleton, 1 through 9. In each case there are also 9 possible values for the triplet. For example if the singleton was a 1, the triplets could be anything but a 1: 1000, 1222, 1333, …, 1999. So there are 9 * 9 = 81 cases with the singleton in the first position.

A singleton in the second position can have 10 possible values, 0 through 9. If it’s a 0 there are 9 possible values for the triplet: 1011, 2022, 3033, …, 9099. If it’s anything else there are only 8 possible values for the triplet since the triplet cannot be 0: 2122, 3133, 4144, …, 9199. So there are 9 + (8 * 9) = 81 cases with the singleton in the second position.

The third and fourth positions work just like the second. So the grand total is 81 * 4 = 324.

If you plot the 9000 four-digit integers as a 100 x 90 grid of squares and color the integers with three same digits in red, an interesting pattern occurs:

There are 81 * 4 = 324 such integers.

There are 9000 four-digit integers from 1000 to 9999. Let’s refer to the digit that occurs three times as the triplet and the digit that occurs once as the singleton.

The third and fourth positions work just like the second. So the grand total is 81 * 4 = 324.

If you plot the 9000 four-digit integers as a 100 x 90 grid of squares and color the integers with three same digits in red, an interesting pattern occurs:

(If you zoom in, the four-digit number is printed inside each red square - not sure whether or not that will come through after Quora processes the image.)

Hope this helps!

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