All categories

2 years ago

Mr Coope drives 472 miles in 8 hours. At this rate, how many miles would he drive in 6

Mathematics

1 answer:

KatRina [158]2 years ago

6 0

8hrs = 480mins
6hrs = 360 mins
472/480 = 0.983...
0.983... x 360 = 354
D) 354

You might be interested in

How do you figure out tax percentages?

Grace [21]

Multiply the cost of an item or service by the sales tax in order to find out the total cost. The equation looks like this: Item or service cost x sales tax (in decimal form) = total sales tax. Add the total sales tax to the Item or service cost to get your total cost.
Make sure you put the sales tax into decimal form. You do this by taking the percentage and sliding the decimal point two places to the left:
7.5% sales tax becomes .075 in decimal form
3.4% sales tax becomes .034 in decimal form
5% sales tax becomes .05 in decimal form
Example: $60 (item cost) x .075 (sales tax) = $4.5 total sales tax

4 0

3 years ago

Pls help I’ll give the big brain award or whatever

andre [41]

Answer:

-0

-1

-2

Step-by-step explanation:

300x80=24,000

7 0

3 years ago

Min-jun has a swimming pool that needs to be drained. His pool holds

crimeas [40]

You will need to drain 1016.308 gallons an hour

8 0

3 years ago

Read 2 more answers

Dwayne walks a total of 960 feet around 3 sides of a square city block. Which

Ugo [173]

Answer:

The perimeter is 1280ft

Step-by-step explanation:

Let the side length of the square be s.

Then the distance around three sides is 3s.

According to the question the distance around 3 sides of a square city block is 960 feet.

This implies that:

$3s = 960$

$s = \frac{960}{3}$

$s = 320$

The perimeter of a square is

$p = 4s$

Substitute s=320 to get:

$p = 4(320)$

$p = 1280$

The perimeter is 1280 ft

5 0

3 years ago

Read 2 more answers

2x^2+3x-2, a=0 How do I find the derivative?

Ghella [55]

You can use the definition:

$\displaystyle f'(x) = \lim_{h\to0}\frac{f(x+h)-f(x)}h$

Then if

$f(x) = 2x^2+3x-2$

we have

$f(x+h) = 2(x+h)^2+3(x+h) - 2 = 2x^2 + 4xh+2h^2+3x+3h-2$

Then the derivative is

$\displaystyle f'(x) = \lim_{h\to0}\frac{(2x^2+4xh+2h^2+3x+3h-2)-(2x^2+3x-2)}h \\\\ f'(x) = \lim_{h\to0}\frac{4xh+2h^2+3h}h \\\\ f'(x) = \lim_{h\to0}(4x+2h+3) = \boxed{4x+3}$

I'm guessing the second part of the question asks you to find the tangent line to f(x) at the point a = 0. The slope of the tangent line to this point is

$f'(0) = 4(0) + 3 = 3$

and when a = 0, we have f(a) = f (0) = -2, so the graph of f(x) passes through the point (0, -2).

Use the point-slope formula to get the equation of the tangent line:

y - (-2) = 3 (x - 0)

y + 2 = 3x

y = 3x - 2

5 0

3 years ago