What is the factored form of x^2 -4x-12

EasyElectrics supermarket orders light bulbs from suppliers, AA Electronics and AAA Electronics. EasyElectrics purchases 30% of

saw5 [17]

Answer: (a) 0.006

(b) 0.027

Step-by-step explanation:

Given : P(AA) = 0.3 and P(AAA) = 0.70

Let event that a bulb is defective be denoted by D and not defective be D';

Conditional probabilities given are :

P(D/AA) = 0.02 and P(D/AAA) = 0.03

Thus P(D'/AA) = 1 - 0.02 = 0.98

and P(D'/AAA) = 1 - 0.03 = 0.97

(a) P(bulb from AA and defective) = P ( AA and D)

= P(AA) x P(D/AA)

= 0.3 x 0.02 = 0.006

(b) P(Defective) = P(from AA and defective) + P( from AAA and defective)

= P(AA) x P(D/AA) + P(AAA) x P(D/AAA)

= 0.3(0.02) + 0.70(0.03)

= 0.027

3 0

3 years ago

PLZ HELL FAST WILL GIVE BRAINLIEST

Sauron [17]

${3x}^{2} - 5x = - 8 \\ {3x}^{2} - 5x + 8 = 0$

This equation has the next form:

${ax}^{2} + bx + c = 0$

To find if the equation has two complex solutions we have to check if the discriminant is negative, as follows:

${b}^{2} - 4ac \\ ( { - 5})^{2} - 4 \: . \: 3 \: . \: 8 = 25 - 96 = - 71 < 0$

Then, the first case has two complex solutions.

In the second case,

${2x}^{2} = 6x - 5 \\ {2x}^{2} - 6x + 5 = 0$

The discriminant in this case is:

$( { - 6})^{2} - 4 \: . \: 2 \: . \: 5 = 36 - 40 = - 4 < 0$

Then, the second case has two complex solutions.

In the third case,

$12x = {9x}^{2} + 4 \\ { - 9x}^{2} + 12x - 4 = 0$

The discriminant in this case is:

${12}^{2} - 4 \: . \: ( - 9) \: . \: ( - 4) = 144 - 144 = 0$

Then, the third case has two real solutions.

In the fourth case,

${ - x}^{2} - 10x = 34 \\ { - x}^{2} - 10x - 34 = 0$

The discriminant in this case is:

$( { - 10})^{2} - 4 \: . \: ( - 1) \: . \: ( - 34) = 100 - 136 = - 36 < 0$

Then, the fourth case has two complex solutions.

7 0

2 years ago

Read 2 more answers

Four integers are consecutive terms of an arithmetic sequence. The sum of these four numbers is 24 and the product is 945.Find t

Marta_Voda [28]

When common difference, $d=\sqrt{39}$ then the largest term of these four terms will be $6+3\sqrt{39}$

Let four consecutive terms of AP is,

$a-3d, a-d, a+d, a+3d$

Since, sum of all four terms is 24

So, $a-3d+a-d+a+d+a+3d=24\\\\a=6$

And product is 945

So, $(a-3d)(a+3d)(a-d)(a+d)=945\\\\9d^4-360d^2+351=0\\\\d^4-40d^2+39=0\\\\(d^2-1)(d^2-39)=0\\\\d=1,-1\\d=\sqrt{39}, -\sqrt{39}$

When d= 1, -1 then largest term is 9

When $d=\sqrt{39}, -\sqrt{39}$ then largest term is $6+3\sqrt{39}$

Learn more:

https://brainly.in/question/3719232

7 0

2 years ago

Mr. Tyler has 45 books on a shelf in his classroom. If 80% of the books are fiction, how many fiction books are on the shelf?

Scrat [10]

Answer:

36

Step-by-step explanation:

hello

we need to take 80% of 45

$\dfrac{80*45}{100}=\dfrac{3600}{100}=36$

so there are 36 fiction books

hope this helps

4 0

3 years ago

Read 2 more answers

64^1-3n • 16^3n-3 = 64^-3n-3

BigorU [14]

The answer is

2^6(1-3n)×2^4(3n-3)=2^6(-3n-3).

2^(6-18n)×2^(12n-12)=2^(-18n-18).

(6-18n)×(12n-12)=(-18n-18).

6-18n×12n-12=18n-18.

6-12×-18n-12n=18n-18

-6×-30n=18n-18.

-6×18=-18+30

-108=48n.

n= -108/48.

n=-2.25.

6 0

3 years ago