Find n for the sequence for which an = 37, a1 = -13 and d = 5.
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Answer:
See attachment
Step-by-step explanation:
The given system is
2x-y=4
x-y=-2
We write the system in slope-intercept form:
y=2x-4
y=x+2
The first equation has slope of 2 and y-intercept at (0,-4)
When y=0, x=2.
We plot (0,-4) and (2,0) to graph this first equation.
The second equation has a slope of 1 and a y-intercept at (0,2)
Also when y=0, x=-2.
We plot (0,2) and (-2,0) and draw a straight line through them.
The graph of the system is shown in the attachment.
The function F(x) have a vertical asymptote at x =0 and x =1.
Given that
The given Function;
We have to determine
At which value the function F(x) has a vertical asymptote.
According to the question
The given Function;
The function is undefined when the denominator becomes 0. Find values of x for which the denominator is 0:
Then,
The value of x is 0 and 1.
Hence, the function F(x) have a vertical asymptote at x =0 and x =1.
To know more about Parabola click the link given below.