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3 years ago

Find n for the sequence for which an = 37, a1 = -13 and d = 5.

1 answer:

5 0

The equation for a sequence is
an=a1+(n-1)d
Replace the variable with what you were given you get
37=-13+(n-1)5
Simplify
37=-13+5n-5
Combine like terms
37=5n-18
Reverse operations
55=5n
Simplify
n=11

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Im in 6th grade and my homwork asks What is 5+6-18+694*88/92+33-11*2,515-55+45*6=? I need help.

just olya [345]

It's -26760.173913043

5 0

3 years ago

Someone pls help me!!!!

tresset_1 [31]

Answer:

Step-by-step explanation:

1 X 26 = 26

2 X 26 = 52

3 X 26 = 78

how is tat algebra???

7 0

3 years ago

Explain why f(x) = x^2+4x+3/x^2-x-2 is not continuous at x = -1.

liberstina [14]

Answer:

The value of x = -1 makes the denominator of the function equal to zero. That is why this value is not included in the domain of f(x)

Step-by-step explanation:

We have the following expression

$f(x) = \frac{x^2+4x+3}{x^2-x-2}$

Since the division between zero is not defined then the function f(x) can not include the values of x that make the denominator of the function zero.

Now we search that values of x make 0 the denominator factoring the polynomial $x^2-x-2$

We need two numbers that when adding them get as a result -1 and when multiplying those numbers, obtain -2 as a result.

These numbers are -2 and 1

Then the factors are:

$(x-2) (x + 1)$

We do the same with the numerator

$x^2+4x+3$

We need two numbers that when adding them get as a result 4 and when multiplying those numbers, obtain 3 as a result.

These numbers are 3 and 1

Then the factors are:

$(x+3)(x + 1)$

Therefore

$f(x) = \frac{(x+3)(x+1)}{(x-2)(x+1)}$

Note that $\frac{(x+1)}{(x+1)}=1$ only if $x \neq -1$

So since $x = -1$ is not included in the domain the function has a discontinuity in $x = -1$

3 0

3 years ago

Someone please help me I have to show how they're similar

Sidana [21]

Angle AXD = angle CXB (vertically opposite angle)
then angle ADB = angle ABC
then angle DAB = angle BCD
I couldn't remember the name of the rule
I said that they are equal if you look at the curve AC and DB
They called them that two angles that subtended by the same mirror (arc)
lead them to be a similar angle (angle - angle - angle)

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3 years ago

a 400 g of a liquid of density 1.6g/cm3 is made from mixing liquids of density 1.2g/cm3 and 1.8g/cm3 find the mass of the liquid

gogolik [260]

Answer:

133.33g

Step-by-step explanation:

Let the:

Mass of 1.2g/cm³ of liquid = x

Mass of 1.8g/cm³ of liquid = y

From our Question above, our system of equations is given as:

x + y = 400........ Equation 1

x = 400 - y

1.2 × x + 1.8 × y = 1.6 × 400

1.2x + 1.8y = 640..... Equation 2

We substitute, 400 - y for x in Equation 2

1.2(400 - y) + 1.8y = 640

480 - 1.2y + 1.8y = 640

- 1.2y + 1.8y = 640 - 480

0.6y = 160

y = 160/0.6y

y = 266.67 g

Solving for x

x = 400 - y

x = 400 - 266.67g

x = 133.33g

Therefore, the mass of the liquid of density 1.2g/cm³ is 133.33g

7 0

3 years ago