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Brrunno [24]
3 years ago
10

Prove that the value of the expression: (125^2+25^2)(5^2-1) is divisible by 39

Mathematics
2 answers:
slavikrds [6]3 years ago
7 0

Answer:

10000*39

Step-by-step explanation:

Simplify the equation fully.

(125 + 25)(5 - 1)

(15625 + 625)(25 - 1)

(16250)(24)

390000

Divide the answer by 39

390000/39 = 10000

babymother [125]3 years ago
3 0

Answer:

10000 * 39

Step-by-step explanation:

(125^2+25^2)(5^2-1)

Rewriting

(5^3^2+5^2^2)(5^2-1)

We know that a^b^c = a^ ( b*c)

(5^(3*2)+5^(2*2))(5^2-1)

(5^6+5^4)(5^2-1)

Factor out 5^4

5^4( 5^2 +1)(5^2-1)

5^4 ( 26) (24)

Factor

5^4 ( 13*2) (3*8)

Rearrange the order

5^4 ( 13*3) (2*8)

5^4 *39 *16

625 * 16 * 39

10000 * 39

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Answer:

a + b \geq 30

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Step-by-step explanation:

Given

The sum of the two positive integer a and b is at least 30, this means the sum of the two positive integer is 30 or greater than 30, so we write the inequalities as below.

a + b \geq 30

The difference of the two integers is at least 10, if b is the greater integer then we subtract integer a from integer b, so we write the inequality as below.

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Therefore, the following system of inequalities could represent the values of two positive integers a and b.

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