W^2+2w-42=0 what is the width and the length
2 answers:
9514 1404 393
Answer:
- width: 5.557 m
- length: 7.557 m
Step-by-step explanation:
<u>Given</u>:
a rectangular patio of width w meters, length w+2 meters, and area 42 m²
<u>Find</u>:
width and length
<u>Solution</u>:
The area is ...
A = LW
42 = w(w +2)
43 = w² +2w +1 . . . . . . add 1 to complete the square
√43 = w+1
w = √43 -1 ≈ 5.557 . . . meters
l = w+2 = √43 +1 ≈ 7.557 . . . meters
The width and length of the patio are 5.557 m and 7.557 m, respectively.
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Answer:
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Step-by-step explanation:
has:
1) amplitude=|a|
2) phase shift=b
3) period=2pi/c
d) vertical shift=d
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You are given the amplitude is 2. This means a could either be 2 or -2.
You are given phase shift is -1/8. This means b is -1/8.
You are given the period is pi. So we need to solve pi=2pi/c.
pi=2pi/c
Dividing both sides by pi gives:
1=2/c
Multiply both sides by c gives:
c=2
The vertical shift is -2 so d=-2.
The equation could either be:
y=2cos(2(x-(-1/8)))-2
or
y=-2cos(2(x-(-1/8)))-2
Simplifying a little gives:
y=2cos(2x+1/4)-2
y=-2cos(2x+1/4)-2