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Arada [10]
3 years ago
7

Graph the image of Q(-8, 2) after a rotation 90° counterclockwise around the origin.

Mathematics
1 answer:
True [87]3 years ago
7 0

Answer:

djfbkthuiyguhfdmc.v

Step-by-step explanation:

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A freezer has a volume of 54 ft.³ it has a length of 6 feet and a height of 3 feet what is the length of the width of the freeze
gogolik [260]
Ok so let’s see we have L and H but we don’t have the W so to find it we start by multiplying the numbers we do have which is L and H so 6x3=18 know that we did that we tasked the volume number which is 54 and we divide that by 18 so 54➗18 = 3 so our width is 3

Hope this helped :)
3 0
1 year ago
Please help me with this math problem!! Will give brainliest!! :)
Greeley [361]

Answer: -12 but could be wrong

Step-by-step explanation:

I don't know that format but I'm going to take a guess.

x^2 +2x - 8 -(2x+8) then plug in x=2

x^2 + 2x - 8 - 2x - 8

x^2 -16

= 2^2 - 16 = -12

5 0
1 year ago
Simplify this number 300mm:9m​
DIA [1.3K]

Answer:

1 : 30

Step-by-step explanation:

300mm:9m​

We need to change the meters to mm

1 meter is 1000 mm

so 9 m is 9000 mm

300mm:9000mm

Divide both sides by 300

​300mm/300 : 9000/300

1 : 30

5 0
3 years ago
the perimeter of a rectangle brownie pan is 50 Inches. the lenght of the pan is 5 less than twice the width. write a system of e
Serga [27]

Answer: The system of equation is,

2 ( x + y ) = 50

x = 2 y - 5

Step-by-step explanation:

Let x represents the length of the rectangular brownie and y represents the width of the rectangular brownie.

Thus, the perimeter of the brownie = 2 ( x + y )

But, According to the question,

Perimeter of the brownie = 50,

2 ( x + y ) = 50

The length of the brownie is 5 less than twice the width,

That is, x = 2 y - 5

Thus, the required system of equation is,

2 ( x + y ) = 50 , x = 2 y - 5


6 0
3 years ago
To find the interquartile range you need to ____the upper and lower quartile values.​
Blababa [14]

Answer:

The correct options are: Interquartile ranges are not significantly impacted by outliers. Lower and upper quartiles are needed to find the interquartile range. The data values should be listed in order before trying to find the interquartile range. The option Subtract the lowest and highest values to find the interquartile range is incorrect because the difference between lowest and highest values will give us range. The option A small interquartile range means the data is spread far away from the median is incorrect because a small interquartile means data is nor spread far away from the median

8 0
2 years ago
Read 2 more answers
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