Secondary or both primary and secondary
It’s either one I believe
-<3 sorry if I’m wrong!
So using a(2)=0 we can first solve for k by substituting t for 2
0 = (2-k)(2-3)(2-6)(2+3)
0 = (2-k)(-1)(-4)(5)
0 = (2-k)20
0 = 40 - 20k
-40 = -20k
k = 2
The next step would be to find all the 0s of a.
0 = (t-2)(t-3)(t-6)(t+3)
T = 2,3,6,-3
Then we find the product
2x3x6x-3 = -108
Since the problem asks for the absolute value, the answer is positive 108
Answer:
-50
Explanation:
Sum of 6 + sum of 4 = -100
100 + sum of 4 = -100
sum of 4 = -200
Avg of 4 = -200/4 = -50
<span> It's locked away in glaciers (in ice).</span>
