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3 years ago

Combine the like terms to create an equivalent expression. k + k + k *

Mathematics

1 answer:

Ilia_Sergeevich [38]3 years ago

7 0

Answer:

Step-by-step explanation:

Ok, so pretend each k has a 1 in front of it. so 1k+1k+1k= 3k. If you need a different equation, you can do 2k+1k=3k or something like that. :)

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Angle A, angle B, and angle C are complementary angles. The measure of angle A is 24 degrees. The measure of angle B is unknown,

tester [92]

Answer: B = 18 degrees

C = 48 degrees

Step-by-step explanation:

Complimentary angles are angles whose sum is 90 degrees.

Angle A, angle B, and angle C are complementary angles. This means that

A + B + C = 90- - - - - - - - - - - - -1

The measure of angle C is twice the measure of angle A. If the measure of angle A is 24 degrees, it means that the measure of angle C would be 2 × 24 = 48 degrees.

Substituting A = 24 and C = 48 into equation 1, it becomes

24 + B + 48 = 90

72 + B = 90

B = 90 - 72

B = 18 degrees

7 0

3 years ago

Imagine you're on a game show, and you're given the choice of three doors: Behind one door is a million dollars, and behind the

Sophie [7]

Always stay not matter what happens if you change you will loose

6 0

3 years ago

What is. Equivalent to 188/11

gulaghasi [49]

Hi!

An equivalent fraction to 188/11 would be 376/22. By multiplying each number in the fraction by 2, you can get an equivalent fraction in return.

Hopefully, this helps! =)

3 0

3 years ago

Read 2 more answers

Ex 4.8 14) integrate 3^(2x-1)

sesenic [268]

Take the integral:

$\large\begin{array}{l} \mathsf{\displaystyle\int\!3^{2x-1}\,dx}\\\\ =\mathsf{\displaystyle\int\!\frac{1}{2}\cdot 2\cdot 3^{2x-1}\,dx}\\\\ =\mathsf{\displaystyle\frac{1}{2}\int\!3^{2x-1}\cdot 2\,dx\qquad(i)} \end{array}$

$\large\begin{array}{l} \textsf{Substitute}\\\\ \mathsf{2x-1=u\quad\Rightarrow\quad 2\,dx=du}\\\\\\ \textsf{so (i) becomes}\\\\ =\mathsf{\displaystyle\frac{1}{2}\int\!3^u\,du}\\\\ =\mathsf{\dfrac{1}{2}\cdot \dfrac{1}{\ell n\,3}\,3^u+C}\\\\ =\mathsf{\dfrac{1}{2\,\ell n\,3}\,3^{2x-1}+C} \end{array}$

$\large\begin{array}{l} \boxed{\begin{array}{c}\mathsf{\displaystyle\int\!3^{2x-1}\,dx=\frac{1}{2\,\ell n\,3}\,3^{2x-1}+C} \end{array}}\qquad\checkmark \end{array}$

If you're having problems understanding this answer, try seeing it through your browser: brainly.com/question/2154165

$\large\textsf{I hope it helps. :-)}$


Tags: integrate indefinite integral substitution exponential base logarithm log ln composite integral calculus

4 0

3 years ago

1. please with justification

Gennadij [26K]

Answer:

1.)-There are the same amount of negative whole numbers as there are positive. It is just on the other end of the number line.

-A natural number is obviously occurring in nature as well so it has to be common like something 1-100 or in the hundreds, not something in the hundred thousands or millions.

-No it just needs to be not a fraction or decimal.

2.)your answer would be E

Hope this is helpful to you!!

5 0

3 years ago