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shtirl [24]
2 years ago
8

PLEASE HELP, ILL GIVE BRAINLIEST! SIMPLE MATHS.

Mathematics
2 answers:
dusya [7]2 years ago
7 0
The answer is c i’m pretty sure
hjlf2 years ago
6 0
The answer is c i think sorry if i am wrong
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Otse verharan's office maskiner weighed 550 grams on the second visit the kinen had gained 350 grams. On the two visit the
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63.64%

Step-by-step explanation:

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Which value lies between 8 and 9 on a number line?
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The answer is root 70
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A tobacco company claims that the amount of nicotene in its cigarettes is a random variable with mean 2.2 and standard deviation
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Answer:

0% probability that the sample mean would have been as high or higher than 3.1 if the company’s claims were true.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 2.2, \sigma = 0.3, n = 100, s = \frac{0.3}{\sqrt{100}} = 0.03

What is the approximate probability that the sample mean would have been as high or higher than 3.1 if the company’s claims were true?

This is 1 subtracted by the pvalue of Z when X = 3.1. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{3.1 - 2.2}{0.03}

Z = 30

Z = 30 has a pvalue of 1.

1 - 1 = 0

0% probability that the sample mean would have been as high or higher than 3.1 if the company’s claims were true.

4 0
3 years ago
The students in Mr. Bhatia's
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Answer:

Isabel's bee rounds to 0.8 inches and Pablo's bee round to 0.5 inches..

Step-by-step explanation:

Look at the attached picture.

The students in Mr. Bhatia's  class measure the length of four bees.

If we round the lengths to the nearest tenth we get:

Isabel’s bee rounds to 0.8 inches

Pablo’s bee rounds to 0.5 inches

Wendi’s bee rounds to 0.6 inches

Brett’s bee rounds to 0.7 inches

This shows that Isabel's bee rounds to 0.8 inches and Pablo's bee round to 0.5 inches..

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3 years ago
Plz answer this I really need this
kiruha [24]

Answer:

D prefer romance over poetry 2:1

Step-by-step explanation:

Poetry is 20%

Romance is 40%

\frac{40}{20} =\frac{2}{1}

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