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3 years ago

Which solid of revolution is produced by rotating the shape below 360° about the given axis?

Mathematics

1 answer:

maxonik [38]3 years ago

5 0

<h3>Answer: Choice A</h3>

Explanation:

When we rotate a rectangle around an axis of symmetry, we end up with a cylinder. Think of a revolving door or a turbine. The flat door moves through 3D space to produce or carve out a 3D cylinder.

This figure is composed of two rectangles, so we'll end up with two cylinders. They will both share the same center, so we'll have a sideways two-layer wedding cake structure when everything is said and done. This points to choice A as the final answer.

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Helpppp meeee question 1 pleaseee !!!

love history [14]

Answer:

2 0 -2 -4

Step-by-step explanation:

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3 years ago

Read 2 more answers

7) 4b2 + 8b + 7 = 4<br> What the answer

Anit [1.1K]

4b² + 8b + 3 = 0

4b² + 2b + 6b + 3 = 0

2b(2b + 1) + 3(2b + 1) = 0

(2b + 3)(2b + 1) = 0

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3 years ago

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Rob Herndon, an accountant with Southwest Airlines, wants to retire 50% of

valina [46]

To achieve his goal of paying off $430,000 in 10 years, Rob Herndon needs to make $34,186.97 at 5% compounded annually.

<h3>What is a future value?</h3>

A future value refers to a value on a future date based on an assumed growth rate of interest over time.

The future value can be determined using the FV formula or table.

We can also compute the future value using an online finance calculator as follows:

<h3>Data and Calculations:</h3>

N (# of periods) = 10 years

I/Y (Interest per year) = 5%

PV (Present Value) = $0

FV (Future Value) = $430,000

<u>Results:</u>

PMT = $34,186.97

Sum of all periodic payments = $341,869.70

Total Interest= $88,130.30

Thus, for Rob Herndon to achieve his goal of paying off $430,000 in 10 years, he needs to make $34,186.97 at 5% compounded annually.

Learn more about Calculating Future Values at brainly.com/question/24703884

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2 years ago

Prove that tan60+tan70-tan50+tan10=2sqrt3?

LiRa [457]

{tan(60) + tan(10)}/{1 - tan(60)*tan(10)} - {tan(60) - tan(10)}/{1 + tan(10)*tan(60)}

<span>ii) Taking LCM & simplifying with applying tan(60) = √3, the above simplifies to: </span>

<span>= 8*tan(10)/{1 - 3*tan²(10)} </span>

<span>iii) So tan(70) - tan(50) + tan(10) = 8*tan(10)/{1 - 3*tan²(10)} + tan(10) </span>

<span>= [8*tan(10) + tan(10) - 3*tan³(10)]/{1 - 3*tan²(10)} </span>

<span>= [9*tan(10) - 3*tan³(10)]/{1 - 3*tan²(10)} </span>

<span>= 3 [3*tan(10) - tan³(10)]/{1 - 3*tan²(10)} </span>

<span>= 3*tan(30) = 3*(1/√3) = √3 [Proved] </span>

<span>[Since tan(3A) = {3*tan(A) - tan³(A)}/{1 - 3*tan²(A)}, </span>
<span>{3*tan(10) - tan³(10)}/{1 - 3*tan²(10)} = tan(3*10) = tan(30)]</span>

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3 years ago

Suppose that a sample of size 100 is to be drawn from a population with standard deviation L0. a. What is the probability that t

NARA [144]

Answer:

The probability that the sample mean will lie within 2 values of μ is 0.9544.

Step-by-step explanation:

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