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Katen [24]
3 years ago
12

Describe how to translate the graph of y=√x to obtain the graph of y=√x-4

Mathematics
2 answers:
Korvikt [17]3 years ago
4 0

Answer:

Shifted to right by 4 units.

Step-by-step explanation:

We have been given a function y=\sqrt{x}. We are asked to find the translation rule to obtain the function y=\sqrt{x-4} from y=\sqrt{x}.

Let us recall translation rules.

f(x)\rightarrow f(x-a)=\text{Graph shifted to right by a units}  

f(x)\rightarrow f(x+a)=\text{Graph shifted to left by a units}

f(x)\rightarrow f(x)+a=\text{Graph shifted upwards by a units}  

f(x)\rightarrow f(x)-a=\text{Graph shifted downwards by a units}

We can see that -4 is under radical, therefore, the function y=\sqrt{x} is shifted to right by 4 units to obtain the graph of y=\sqrt{x-4}.

Genrish500 [490]3 years ago
3 0
If the -4 is NOT under the radical sign the graph would move DOWN four units on the y axis.

If the -4 is under the radical sign the graph would move 4 units to the RIGHT on the x-axis.
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Alfred has 10 more tokens than Clarissa. Clarissa has twice as many tokens as Benji. They have 85 tokens altogether. How many to
marysya [2.9K]

Answer:

Alfred has 40 tokens

Clarissa has 30 tokens

Benji has 15 tokens

Step-by-step explanation:

Let's give each person a variable:

A for Alfred

C for Clarissa

B for Benji

Now, we can take what the question is saying and convert them into equations:

Alfred has 10 more tokens than Clarissa can look like this:

A = C + 10

Since Alfred has 10 more coins than Clarissa we can take C and add 10 to find how many tokens Alfred has.

Clarissa has twice as many tokens as Benji looks like this:

C = 2B

Since Clarissa has twice as many tokens as Benji we can multiply B (how many tokens Benji has) by 2.

Lastly, they have 85 tokens all together:

A + B + C = 85

We have these 3 equations:

A = C + 10

C = 2B

A + B + C = 85

Now, we can substitute some variables:

A = (2B) + 10    Since C is equal to 2B we can substitute 2B in for C in the first equation.

We have found what A equals, we can plug that in to the last equation:

(2B) + 10 + B + C = 85

We can also substitute the second equation into the third equation:

(2B) + 10 + B + 2B = 85

Combine like terms:

5B + 10 = 85

Solve

5B = 75

B = 15

This means that Benji has 15 tokens. Now we can find how much the other children have:

C = 2(15) = 30

Clarissa has 30 tokens

A = 30 + 10

A = 40

Alfred has 40 tokens.

<u>Answer:</u>

Alfred has 40 tokens

Clarissa has 30 tokens

Benji has 15 tokens

<u>Checking the Answer</u>

A + B + C = 85

40 + 15 + 30 = 85

85 = 85

<em>I hope this helps!!</em>

<em>- Kay :)</em>

6 0
3 years ago
15 points answer ,,,,,,,,,,,,,,,,,,,,,,,,
densk [106]
6/16 is the correct answer enjoy
6 0
4 years ago
A 0.1 significance level is used for a hypothesis test of the claim that when parents use a particular method of gender​ selecti
Andrews [41]

Answer:

(a) Null Hypothesis, H_0 : p = 0.50

    Alternate Hypothesis, H_A : p > 0.50

(b) The value of level of significance (α) given in the question is 0.10.

(c) The sampling distribution of the sample statistic is Normal distribution.

(d) This test is right-tailed.

(e) The value of z test statistics is 0.96.

(f) The P-value is 0.1685.

(g) At 0.10 significance level the z table gives critical value of 1.282 for right-tailed test.

(h) We conclude that the proportion of baby girls is equal to 0.50.

Step-by-step explanation:

We are given that a 0.1 significance level is used for a hypothesis test of the claim that when parents use a particular method of gender​ selection, the proportion of baby girls is greater than 0.5.

Assume that sample data consists of 78 girls in 144 ​births.

Let p = <u><em>population proportion of baby girls</em></u>

(a) So, Null Hypothesis, H_0 : p = 0.50     {means that the proportion of baby girls is equal to 0.50}

Alternate Hypothesis, H_A : p > 0.50     {means that the proportion of baby girls is greater than 0.50}

(b) The value of level of significance (α) given in the question is 0.10.

(c) The sampling distribution of the sample statistic is Normal distribution.

(d) This test is right-tailed as in the alternative hypothesis we are concerned for proportion of baby girls that is greater than 0.50.

(e) The test statistics that would be used here <u>One-sample z test for proportions</u>;

                             T.S. =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of baby girls =  \frac{78}{144} = 0.54

            n = sample of births = 144

So, <u><em>the test statistics</em></u>  =  \frac{0.54-0.50}{\sqrt{\frac{0.54(1-0.54)}{144} } }  

                                       =  0.96

The value of z test statistics is 0.96.

(f) <u>The P-value of the test statistics is given by;</u>

            P-value = P(Z > 0.96) = 1 - P(Z < 0.96)

                          = 1 - 0.8315 = 0.1685

<u></u>

(g) <u>Now, at 0.10 significance level the z table gives critical value of 1.282 for right-tailed test.</u>

(h) Since our test statistic is less than the critical value of z as 0.96 < 1.282, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region (which was to the right of value of 1.282) due to which <u>we fail to reject our null hypothesis</u>.

Therefore, we conclude that the proportion of baby girls is equal to 0.50.

7 0
3 years ago
Kevin is planting 15 bushes and 9 trees in rows. If he wants all the rows to be exactly the same, with no plants left over, what
Alexandra [31]

Answer:

why is Kevin planting all those trees Kevin should get a job

8 0
3 years ago
(b) Find the angle between u and v to the nearest degree.
yulyashka [42]

<u>Question 1 (b)</u>

<u />u \cdot v=11\\\\|u|=\sqrt{3^{2}+(-1)^{2}}=\sqrt{10}\\\\|v|=\sqrt{4^{2}+1^{2}}=\sqrt{17}

So,

\cos \theta=\frac{11}{\sqrt{10}\sqrt{17}}\\\\\theta=\cos^{-1} \left(\frac{11}{\sqrt{10}\sqrt{17}} \right) \approx \boxed{32^{\circ}}

<u>Question 2 (b)</u>

<u />u \cdot v=22\\\\|u|=\sqrt{5^{2}+2^{2}}=\sqrt{29}\\\\|v|=\sqrt{4^{2}+1^{2}}=\sqrt{17}

So,

\cos \theta=\frac{22}{\sqrt{29}\sqrt{17}}\\\\\theta=\cos^{-1} \left(\frac{22}{\sqrt{29}\sqrt{17}} \right) \approx \boxed{8^{\circ}}

6 0
2 years ago
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