How to expand 3(2t+1)
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Answer:
The probability that the maximum speed is at most 49 km/h is 0.8340.
Step-by-step explanation:
Let the random variable<em> </em><em>X</em> be defined as the maximum speed of a moped.
The random variable <em>X</em> is Normally distributed with mean, <em>μ</em> = 46.8 km/h and standard deviation, <em>σ</em> = 1.75 km/h.
To compute the probability of a Normally distributed random variable we first need to convert the raw score of the random variable to a standardized or <em>z</em>-score.
The formula to convert <em>X</em> into <em>z</em>-score is:
Compute the probability that the maximum speed is at most 49 km/h as follows:
Apply continuity correction:
P (X ≤ 49) = P (X < 49 - 0.50)
= P (X < 48.50)
*Use a <em>z</em>-table for the probability.
Thus, the probability that the maximum speed is at most 49 km/h is 0.8340.
We have to draw the model for 42 divide 7 . In order to draw the model we use below steps.
- Draw 7 boxes to represent 7 groups.
- Assume 42 as the number which represents the total of these 7 groups.
- Put a question mark at the first box.
Attached is the model to represents 42 divide 7 .
In the question mark we should put 6. Hence, when we add 6 to 7 times that will be equal to 42.
