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Kamila [148]
3 years ago
12

The points A, B, C and D lie on a circle centre O.

Mathematics
1 answer:
DENIUS [597]3 years ago
5 0
A I think is the answer
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is anyone good at math here!??!!??!?!?!?!??!?!?!?!? please don't scroll please answerrrrrrrrrrrrrr this for meeeeeeeeeeeeeeeeeee
riadik2000 [5.3K]
I think its B I’m not 100% sure tho
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en la pescaderia de un centro comercial se vende por la mañana 3/4 partes del pescado que tenían. por la tarde se vende 4/5 de l
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3 years ago
Why is -10+(-10)=0 wrong
kenny6666 [7]

Step-by-step explanation:

because because that would be subtracting positive 10 by -10. not adding -10 + -10 which would be 20

5 0
4 years ago
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. If IQ scores are normally distributed with a mean of 100 and a standard deviation of 5, what is the probability that a person
bulgar [2K]

Answer:

2.28% probability that a person selected at random will have an IQ of 110 or greater

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 100, \sigma = 5

What is the probability that a person selected at random will have an IQ of 110 or greater?

This is 1 subtracted by the pvalue of Z when X = 110. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{110 - 100}{5}

Z = 2

Z = 2 has a pvalue of 0.9772

1 - 0.9772 = 0.0228

2.28% probability that a person selected at random will have an IQ of 110 or greater

5 0
3 years ago
What is 80% more than 20.00
AlekseyPX
Answer is 36.
20 * 80/100 = 16
20+16=36
5 0
4 years ago
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