Question

Henry has a fair number pyramid with four faces and a spinner with three equal sized colored sections. what is the probability that the number pyramid will land on three and the spinner will stop on blue?

Answer 1

P(pyramid landing on 3) = 1/4
P(spinner stopping on blue) = 1/3

P(both) = 1/4 * 1/3 = 1/12 <===

Answer 2

Answer: $\dfrac{1}{12}$

Step-by-step explanation:

Given : The number of faces in a fair number pyramid (1,2,3,4) =4

Let A be the event that number pyramid will land on three.

Then, $P(A)=\dfrac{1}{4}$

The number of equal sized colored sections in spinners= 3

Let B be the event that  the spinner will stop on blue.

Then, $P(B)=\dfrac{1}{3}$

Since, both the events A and B are independent.

Thus, the probability that the number pyramid will land on three and the spinner will stop on blue is given by :-

$P(A\cap B)=P(A)\times P(B)\\\\=\dfrac{1}{4}\times\dfrac{1}{3}=\dfrac{1}{12}$

Hence, the probability that the number pyramid will land on three and the spinner will stop on blue =$\dfrac{1}{12}$