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VladimirAG [237]
3 years ago
12

The ratio of students wearing sandals to those wearing sneakers is 5 : 1. If there are 30 students in the class, and all of them

are wearing either sandals or sneakers, how many of them are wearing sandals?can someone anwser this plz:(
Mathematics
1 answer:
Igoryamba3 years ago
7 0

Step-by-step explanation:

5:1 =<u> </u><u>5</u>

<u> </u><u> </u><u> </u> 1

= <u>5</u><u> </u><u> </u>× 30

<u> </u><u> </u><u> </u><u> </u>1

any standing alone is on one so

<u>6</u><u> </u>× <u>3</u><u>0</u>

1 1

<u>1</u><u>8</u><u>0</u>

1

180

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61 × 5 in distributive property ​
Doss [256]

Answer:

305

Step-by-step explanation:

61 x 5 = 305

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2 years ago
In 2015 Michael purchased a stock for $45.80 a share. During the year he received $1.71 per share in cash dividends. At the end
timama [110]
Michael's initial investment is $45.80, the cost of the share. 
Michael Receives $1.71 in dividends.
He receives $47.50 for the stock when he sells it.
His profit on the sale of the stock is $47.50 - 45.80 = $1.70.
His total return on the stock is his total earnings, the dividends plus his profits on the sale of the stock, divided on what he paid initially, $45.80:
(1.71 + 1.70) ÷ 45.80 = .0744 = 7.45%
7.45% return on investment in less than a year, not bad!
Closest answer is 7.7%, not sure why it isn't exactly 7.45 or 7.5%. 

Answer is B) 7.7%
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3 years ago
(g o f)(6)
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A. gof=g(f(x))

= g(f(6))

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7 0
3 years ago
Read 2 more answers
In a sample of 70 stores of a certain​ company, 62 violated a scanner accuracy standard. It has been demonstrated that the condi
uysha [10]

Answer:

We need at least 243 stores.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error of the interval is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

For this problem, we have that:

n = 70, p = \frac{62}{70} = 0.886

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Determine the number of stores that must be sampled in order to estimate the true proportion to within 0.04 with 95​% confidence using the​ large-sample method.

We need at least n stores.

n is found when M = 0.04. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.04 = 1.96\sqrt{\frac{0.886*0.114}}{n}}

0.04\sqrt{n} = 1.96\sqrt{0.886*0.114}

\sqrt{n} = \frac{1.96\sqrt{0.886*0.114}}{0.04}

(\sqrt{n})^{2} = (\frac{1.96\sqrt{0.886*0.114}}{0.04})^{2}

n = 242.5

Rounding up

We need at least 243 stores.

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