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tatuchka [14]
2 years ago
12

Is this a function or not

Mathematics
1 answer:
s344n2d4d5 [400]2 years ago
8 0

this equation is not funcion.

Step-by-step explanation:

if u make a graph and u aline them with dots 2 or more dots will cross each other witch makes it not function:)

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8

Step-by-step explanation:

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Liza went out for pizza with her mom. Their meal cost $32. Sales tax is 5% and they decide to leave 15%
ASHA 777 [7]

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Step-by-step explanation:

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3 years ago
URGENT! 100 POINTS TO SOLVE!
masya89 [10]

Answer:

20/5 = x /4 x = 80/5 = 16

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3 0
2 years ago
Read 2 more answers
Find (a) the number of subsets and (b) the number of proper subsets of the set.
vaieri [72.5K]

Answer:

(a) Total No. of Subsets = 128

(b) Total No. of Proper Subsets = 127

Step-by-step explanation:

First we need to define the set of days of the week.

Set of Days of Week = {Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday}

It is evident from the set of days of the week, that it contains 7 elements.

(a)

The total no. of subsets of a given set is given by the following formula:

Total No. of Subsets = 2^n

where,

n = no. of elements of the set = 7

Therefore,

Total No. of Subsets = 2^n

Total No. of Subsets = 2^7

<u>Total No. of Subsets = 128</u>

(b)

The total no. of proper subsets of a given set is given by the following formula:

Total No. of Proper Subsets = (2^n) - 1

where,

n = no. of elements of the set = 7

Therefore,

Total No. of Proper Subsets = (2^n) - 1

Total No. of Proper Subsets = (2^7) - 1 = 128 - 1

<u>Total No. of Proper Subsets = 127 </u>

3 0
3 years ago
Rewrite the expression 4+<img src="https://tex.z-dn.net/?f=%5Csqrt%7B16-%284%29%285%29%7D" id="TexFormula1" title="\sqrt{16-(4)(
Inessa05 [86]

Answer:

2+i

Step-by-step explanation:

Given the expression:

\dfrac{4+\sqrt{16-(4)(5)}}{2}

To find:

The expression of above complex number in standard form a+bi.

Solution:

First of all, learn the concept of i (pronounced as <em>iota</em>) which is used to represent the complex numbers. Especially the imaginary part of the complex number is represented by i.

Value of i =\sqrt{-1}.

Now, let us consider the given expression:

\dfrac{4+\sqrt{16-(4)(5)}}{2}\\\Rightarrow \dfrac{4+\sqrt{16-(4\times 5)}}{2}\\\Rightarrow \dfrac{4+\sqrt{16-20}}{2}\\\Rightarrow \dfrac{4+\sqrt{-4}}{2}\\\Rightarrow \dfrac{4+\sqrt{(-1)(4)}}{2}\\\Rightarrow \dfrac{4+\sqrt{(-1)}\sqrt4}{2}\\\Rightarrow \dfrac{4+\sqrt4i}{2} \ \ \ \ \ (\because \sqrt{-1} =i) \\\Rightarrow \dfrac{4+2i}{2}\\\Rightarrow 2+i

So, the given expression in standard form is 2+i.

Let us compare with standard form a+bi so we get a =2, b =1.

\therefore The standard form of

\dfrac{4+\sqrt{16-(4)(5)}}{2}

is: \bold{2+i}

8 0
2 years ago
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