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2 years ago

Solve the system of equations and choose the correct answer from the list of options. (4 points)

Mathematics

1 answer:

MrMuchimi2 years ago

3 0

The correct answer you hear me calling you i know u hear my body calling you

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Solve the system of linear equations.

White raven [17]

Answer:

The simple answer, "Yes"

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1 year ago

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Help me please you guys. Been stuck on this one for an hour

nekit [7.7K]

I think the answer is d hope this helps

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2 years ago

What is 27 divide by 6588

Ipatiy [6.2K]

27 / 6588 = 0.00409836065

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2 years ago

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3. What is the slope of the line that contains the

dlinn [17]

Answer:

I think the answer would be -1/2 or D.

Step-by-step explanation:

Use this formula for calculating slope : y2-y1 / x2 - x1

1. label the pairs, 1 and 2

(-6, 1) - ( x1, y1 ) or (4,-4) - (x1, y1)

(4,-4) - ( x2, y2) (-6,1) - (x2, y2)

(the order does not matter)

2. Than plug in your numbers

y2-y1 / x2 -x1 y2-y1 / x2 -x1

-4 - 1 / 4 - (-6) or 1 - (-4) / -6 - 4

= -5/10 or -1/2 = - 5/-10 or -1/2

im only in eight grade so i did my best explaining , and this hope it helps :)

7 0

3 years ago

Let F⃗ =2(x+y)i⃗ +8sin(y)j⃗ .

Alik [6]

Answer:

-42

Step-by-step explanation:

The objective is to find the line integral of $F$ around the perimeter of the rectangle with corners (4,0), (4,3), (−3,3), (−3,0), traversed in that order.

We will use <em>the Green's Theorem </em>to evaluate this integral. The rectangle is presented below.

We have that

$F(x,y) = 2(x+y)i + 8j \sin y = \langle 2(x+y), 8\sin y \rangle$

Therefore,

$P(x,y) = 2(x+y) \quad \wedge \quad Q(x,y) = 8\sin y$

Let's calculate the needed partial derivatives.

$P_y = \frac{\partial P}{\partial y} (x,y) = (2(x+y))'_y = 2\\Q_x =\frac{\partial Q}{\partial x} (x,y) = (8\sin y)'_x = 0$

Thus,

$Q_x -P_y = 0 -2 = - 2$

Now, by the Green's theorem, we have

$\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA = \int \limits_{-3}^{4} \int \limits_{0}^{3} (-2)\,dy\, dx \\ \\\phantom{\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA}= \int \limits_{-3}^{4} (-2y) \Big|_{0}^{3} \; dx\\ \phantom{\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA}= \int \limits_{-3}^{4} (-6)\; dx = -6x \Big|_{-3}^{4} = -42$

4 0

2 years ago