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AURORKA [14]
2 years ago
5

Please solve i got 3 but i’m not sure

Mathematics
1 answer:
GuDViN [60]2 years ago
7 0
Short answer x = 11/3
Step One

Change 64 to a power of 4
\text{64  = 4}^{4}

Step Two
Include 2x - 4 as part of your power. So far you are only working on the right side of the problem.

(x^{4*(2x - 4)}

Step Three
The bases are the same so you can equate the powers.
2x + 6   = 4(2x - 4) 

Step Four
Remove the brackets on the right.
2x + 6 = 8x - 16 

Step five
Collect like terms.     Begin by adding 14 to both sides.
2x + 6 + 16 = 8x       Subtract 2x from both sides.
22 = 8x - 2x
22 = 6x                     Divide by 6
22/6 = x
x = 3.666333 or 3 2/3 or 11/3

Check
Left hand side
4^(2*11/3 + 6) 
4^(22/3 + 6)
4^(22/3 + 18/3)
4^(40/3) 

Right Side
64^(2*11/3 - 4)
64^(22/3 - 4)
64^(22/3 - 12/3)
64^(10/3)    There is something we can do without figuring out what this is.
64 = 4^4
4^(4*10/3)
4^(40/3) which is the same as the left side

Answer x = 11/3 <<<<<
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Step-by-step explanation:

Given the dataset:

{20,22,23,24,26,26,28,29,30}

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 9

Q1 = 1/4 (9 + 1)th term

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B) The interquartile range(IQR) of the dataset :

{62,63,64,65,67,68,68,68,69,74}

IQR = Q3 - Q1

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 10

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We take the average of the 2nd and 3rd term:

(63 + 64) / 2

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The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 10

Q3 = 3/4 (10 + 1)th term

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We take the average of the 8th and 9th term:

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137 / 2 = 68.5

IQR = Q3 - Q1

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IQR = 5

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The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 9

Q3 = 3/4 (9 + 1)th term

Q3 = 3/4(10) = 7.5 term

We take the average of the 7th and 8th term:

(13 + 15) / 2

28 / 2 = 14

7 0
3 years ago
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