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The code that remove duplicate is as follows:
def remove_duplicate(mylist):
mylist = list(dict.fromkeys(mylist))
return mylist
print(remove_duplicate([1, 1, 2, 3, 3, 5, 6, 7]))
<h3>Code explanation</h3>The code is written in python.
- we defined a function named "remove_duplicate" and it accept the parameter "mylist".
- The variable "mylist" is used to store the new value after the duplicate vallues has been removed.
- Then, wed returned mylist.
- Finally, we call the function with the print statement . The function takes the required parameter.
learn more on python here: brainly.com/question/21126936
Answer:
B. {1, 2, 2, 3, 3, 4, 5}
Explanation:
Given
The above code segment
Required
Determine which list does not work
The list that didn't work is
Considering options (A) to (E), we notice that only list B has consecutive duplicate numbers i.e. 2,2 and 3,3
All other list do not have consecutive duplicate numbers
Option B can be represented as:
if (nums.get(j).equals(nums.get(j + 1)))
The above if condition checks for duplicate numbers.
In (B), when the elements at index 1 and 2 (i.e. 2 and 2) are compared, one of the 2's is removed and the Arraylist becomes:
The next comparison is: index 3 and 4. Meaning that comparison of index 2 and 3 has been skipped.
<em>This is so because of the way the if statement is constructed.</em>