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e-lub [12.9K]
3 years ago
11

A twin-engine plane flies 1050 mi in the same amount of time it takes a single engine plane to fly 800 mi. The rate of the is tw

in-engine plane is 50 mph faster than the rate of the single-engine plane. Find the rate of the single engine plane.
Mathematics
1 answer:
Ostrovityanka [42]3 years ago
4 0
The correct answer is B
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The diagram shows the dimensions of a new parking lot at Helen's Health Food store. 45 yd g41307181 35 yd The parking lot is squ
andreev551 [17]

Answer:

1575 sq yards

Step-by-step explanation:

because.....

45 multiplied by 35 gives you your answer

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100+points &amp; Brainliest<br><br> what is the simplified form of y2 + 7y + 12 / y2 + 8y + 15
Fantom [35]
(y^2 + 7y +12) / (y^2+8y +15)

factor both equations:

(y+3)(y+4) / (y+3) (y+5)

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3 years ago
1.8 + 45 tenths = ___
Ket [755]

Answer: 6.3

Step-by-step explanation:

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8 0
3 years ago
Given sintheta =7/11 and sectheta is less than 0, find costheta and tantheta
Korvikt [17]

Answer:

Step-by-step explanation:

Sin theta is the ratio of side opposite over hypotenuse of a reference angle situated at the origin in an x-y coordinate plane.  If sec theta is negative, then the only quadrant where sin is positive AND sec is negative is quadrant 2.  Remember that sec theta is the inverse of cos theta.  Puttling our right triangle in QII, the side measuring 7 is across from the angle and the hypotenuse is 11.  In order to find the cos theta and tan theta, we need the side adjacent to the angle.  Use Pythagorean's Theorem to find the side adjacent.

11^2=7^2+x^2 and

121=47+x^2 and

72=x^2 so

x=6\sqrt{2}

Remember that this value is why the sec is negative.  Because x is negative in QII, the cos theta is side adjacent over hypotenuse:

cos\theta=-\frac{6\sqrt{2} }{11}  and

tan\theta=-\frac{7}{6\sqrt{2} }

But we should probably rationalize that denominator, so

tan\theta=-\frac{7}{6\sqrt{2} }*\frac{\sqrt{2} }{\sqrt{2} } =-\frac{7\sqrt{2} }{12}

5 0
3 years ago
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