How do i solve y=ln(2x)

1 answer:

5 0

As we know, e and ln(x) are inverses of each other. We can use this to our advantage by having e as a base, and raising both the sides of the equation:
$e^{y} = e^{ln(2x)}$

This simplifies down to (using ln(x) properties):
$e^y = 2x$

Solve for x to get:
$x = \frac{e^y}{2}$

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Find the balance in an account with $7,000 principal earning 5% interest compounded quarterly

nadya68 [22]

Answer:

The balance is $\$11,505.34$

Step-by-step explanation:

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$t=10\ years\\ P=\$7,000\\ r=0.05\\n=4$

substitute in the formula above

$A=\$7,000(1+\frac{0.05}{4})^{4*10}=\$11,505.34$

3 0

4 years ago

Total power generated by wind worldwide doubles every 3 years. In a particular year, the world wind-generating capacity was abou

IceJOKER [234]

<span>You are given the sum of the power created by wind worldwide which doubles every 3 years. In one an unknown year, the world wind generating capacity was about 91 thousand megawatts. You are asked for the growth rate. the growth rate formula is given below:

growth rate = (present / past)^(1/n)
2 = (present/91MW)^(1/3)
the present power is 728MW</span>

7 0

3 years ago

How do I solve

Maslowich

$Use:\\\\(ab)^n=a^nb^n\\\\(a^n)^m=a^{nm}\\\\a^n\cdot a^m=a^{n+m}\\\\\sqrt[n]{a}=a^\frac{1}{n}\\------------------------\\\\\left(16n^4\right)^{\frac{5}{4}}=16^\frac{5}{4}\left(n^4\right)^\frac{5}{4}=16^{1\frac{1}{4}}n^{4\cdot\frac{5}{4}}=16^{1+\frac{1}{4}}n^5=16^1\cdot16^\frac{1}{4}\cdot n^5\\\\=16\cdot\sqrt[4]{16}\cdot n^5=16\cdot2\cdot n^5=\boxed{32n^5}\\\\\sqrt[4]{16}=2\ because\ 2^4=16\\\\\text{Answer}\ \boxed{\left(16n^4\right)^\frac{5}{4}=32n^5}$