You're looking for a value
such that
Because the distribution is symmetric, the value of
in either case will be the same.
Now, because the distribution is continuous, you have that
The mean for the standard normal distribution is
, and because the distribution is symmetric about its mean, it follows that
.
You can consult a
score table to find the corresponding score for this probability. It turns out to be
.
Answer:
At 5% significance level, it is statistically evident that there is nodifference in the proportion of college students who consider themselves overweight between the two poll
Step-by-step explanation:
Given that a poll was taken this year asking college students if they considered themselves overweight. A similar poll was taken 5 years ago.
Let five years ago be group I X and as of now be group II Y
(Two tailed test at 5% level of significance)
Group I Group II combined p
n 270 300 570
favor 120 140 260
p 0.4444 0.4667 0.4561
Std error for differene = 
p difference = -0.0223
Z statistic = p diff/std error = -1.066
p value =0.2864
Since p value >0.05, we accept null hypothesis.
At 5% significance level, it is statistically evident that there is nodifference in the proportion of college students who consider themselves overweight between the two poll
Answer:
1. 81
2. 108 1/2
3. 189 1/2
Step-by-step explanation:
Answer:1 1/5 dozen cookies a hour
Step-by-step explanation: hope it helps
Answer: $250
Step-by-step explanation: Step 1: Multiply $50 by 4 Step 2: Subtract $450 by $250 Step 3: Then you get $200 leftover
