Luther evaluated 2^3 as 9 and wade evaluated 3^2 as 9 are both students correct?
2 answers:
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Answer:
The graph in the attached figure
Step-by-step explanation:
we have
Remember that in a quotient, the denominator cannot be equal to zero
so
The value of x cannot be equal to x=-2
Simplify the expression
Using a graphing tool
The roots of the quadratic equation in the numerator are
x=-2 and x=1
so
Simplify the denominator
substitute in the original expression
Simplify
Is the equation of a line
The y-intercept is the point (0,-3) (value of the function when x is equal to zero)
The x-intercept is the point (1,0) (value of x when the value of the function is equal to zero)
Graph the line, but remember that the value of x cannot be equal to -2
The graph in the attached figure
Answer:
(A'B'): 3 1/2 IN.
(D'E'): 2 1/2 IN.
(R'S'): 4 IN.
Step-by-step explanation:
Just slice the numbers in half
Also i took the test.
