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3 years ago

14

This box is a right rectangular prism with a base that has dimensions of 6 m and 7 m. The volume of the box is 378 m3. What is t

he height of this box?

2 answers:

tigry1 [53]3 years ago

8 0

Answer: 9

Step-by-step explanation:

i got it right

Over [174]3 years ago

5 0

Answer:

29.07m³

Step-by-step explanation:

7+6=13

378÷13=29.07m³

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Henry can type 3500 words in 70 minutes. Colin can type 1500 in 30 minutes. Brian can type 2200 words in 40 minutes. Who types a

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Given:

Henry can type 3500 words in 70 minutes.

Colin can type 1500 in 30 minutes.

Brian can type 2200 words in 40 minutes.

To find:

The person who types at the fastest rate of words per minute.

Solution:

We know that,

$\text{Rate of words per minute}=\dfrac{\text{Number of words}}{\text{Number of minutes}}$

Using this formula, we get

$\text{Henry's rate of words per minute}=\dfrac{3500}{70}=50$

$\text{Colin's rate of words per minute}=\dfrac{1500}{30}=50$

$\text{Brian's rate of words per minute}=\dfrac{2200}{40}=55$

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3 years ago

9. A circle has an arc of length 56pi that is intercepted by a central angle of 120 degrees. What is the radius of the circle?

SSSSS [86.1K]

Answer:

Part 4) $r=84\ units$

Part 9) $sin(\theta)=-\frac{\sqrt{5}}{3}$

Part 10) $sin(\theta)=-\frac{9\sqrt{202}}{202}$

Step-by-step explanation:

Part 4) A circle has an arc of length 56pi that is intercepted by a central angle of 120 degrees. What is the radius of the circle?

we know that

The circumference of a circle subtends a central angle of 360 degrees

The circumference is equal to

$C=2\pi r$

using proportion

$\frac{2\pi r}{360^o}=\frac{56\pi}{120^o}$

simplify

$\frac{r}{180^o}=\frac{56}{120^o}$

solve for r

$r=\frac{56}{120^o}(180^o)$

$r=84\ units$

Part 9) Given cos(∅)=-2/3 and ∅ lies in Quadrant III. Find the exact value of sin(∅) in simplified form

Remember the trigonometric identity

$cos^2(\theta)+sin^2(\theta)=1$

we have

$cos(\theta)=-\frac{2}{3}$

substitute the given value

$(-\frac{2}{3})^2+sin^2(\theta)=1$

$\frac{4}{9}+sin^2(\theta)=1$

$sin^2(\theta)=1-\frac{4}{9}$

$sin^2(\theta)=\frac{5}{9}$

square root both sides

$sin(\theta)=\pm\frac{\sqrt{5}}{3}$

we know that

If ∅ lies in Quadrant III

then

The value of sin(∅) is negative

$sin(\theta)=-\frac{\sqrt{5}}{3}$

Part 10) The terminal side of ∅ passes through the point (11,-9). What is the exact value of sin(∅) in simplified form?

see the attached figure to better understand the problem

In the right triangle ABC of the figure

$sin(\theta)=\frac{BC}{AC}$

Find the length side AC applying the Pythagorean Theorem

$AC^2=AB^2+BC^2$

substitute the given values

$AC^2=11^2+9^2$

$AC^2=202$

$AC=\sqrt{202}\ units$

so

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simplify

$sin(\theta)=\frac{9\sqrt{202}}{202}$

Remember that

The point (11,-9) lies in Quadrant IV

then

The value of sin(∅) is negative

therefore

$sin(\theta)=-\frac{9\sqrt{202}}{202}$

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The answer is a because I wired it out

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3 years ago

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Answer: no

Step-by-step explanation:

No it is not evenly divided ( 6.8888)

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