Answer:
Length of sides of poster = 2 Ft
Length of sides of box = 2.41 Ft
Since the box has a longer side than the poster, the poster will lie flat when placed in the box.
Step-by-step explanation:
In order to determine if the poster will lie flat in the box or not, we will determine the length of the sides of the poster and the box, if the length of the side of the square poster is smaller than that of the box, it will lie flat. This is calculated as follows:
Area of poster = 4 square feet
Area of poster = (Length)²
4 = (Length)²
∴ Length = √(4)
Length of poster = 2 Ft
Volume of box = 14 cubic feet
Volume of box = (Length)³
14 = (Length)³
∴ Length = ∛(14)
Length = 2.41 Ft
∴ Length of sides of poster = 2 Ft
Length of sides of box = 2.41 Ft
Since the box has a longer side than the poster, the poster will lie flat when placed in the box.
The 6 terms of the series are
... 15, 14, 13, 12, 11, 10
The sum of them is 75.
_____
You could make use of the formula for the sum of the terms, or you could work out the sum from the given expression. It is easier just to list the terms and and them up.
Answer:
this isn't a specific question you need to be more specific
Step-by-step explanation:
Answer:
(3 x + 5) (x + 5)
Step-by-step explanation:
Factor the following:
3 x^2 + 20 x + 25
Hint: | Factor 3 x^2 + 20 x + 25 by finding factors of 3×25 whose sum is 20.
Factor the quadratic 3 x^2 + 20 x + 25. The coefficient of x^2 is 3 and the constant term is 25. The product of 3 and 25 is 75. The factors of 75 which sum to 20 are 5 and 15. So 3 x^2 + 20 x + 25 = 3 x^2 + 15 x + 5 x + 25 = 5 (3 x + 5) + x (3 x + 5):
5 (3 x + 5) + x (3 x + 5)
Hint: | Factor common terms from 5 (3 x + 5) + x (3 x + 5).
Factor 3 x + 5 from 5 (3 x + 5) + x (3 x + 5):
Answer: (3 x + 5) (x + 5)
