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erik [133]
3 years ago
10

PLEASE HELP DUE!!! WILL GIVE BRAINLIEST!! can someone help me please?

Computers and Technology
1 answer:
drek231 [11]3 years ago
6 0

Answer:

see below picture

Explanation:

You can work your way through the formula from the inside out, mapping every operation to a gate.

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Write another function to convert a value to its word equivalent leveraging the following tuple - o Number = (‘One’, ‘Two’, … ‘N
prohojiy [21]

Answer:

  1. def convertStr(num):
  2.    Number = ("One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine")
  3.    numStr = str(num)
  4.    output = ""
  5.    for x in numStr:
  6.        index = int(x) - 1
  7.        output += Number[index] + " "
  8.    return output
  9. value = 1234
  10. print(convertStr(value))

Explanation:

Firstly, create a function convertStr that take one input number (Line 1).

This function convert the input number to string (Line 3) and then use for-loop to traverse through the individual digit (Line 6). In the loop, get the target index to extract the corresponding digit letter from the Number tuple(Line 7). The target index is always equal to the current digit number - 1. Next, join the extracted digit letter from the tuple to an output string (Line 8) and return it at the end of the function (Line 10).

We test the function using 1234 as argument (Line 12 - 13) and we shall get One Two Three Four

7 0
3 years ago
Write Album's PrintSongsShorterThan() to print all the songs from the album shorter than the value of the parameter songDuration
lidiya [134]

Answer:

kindly check explainations for code

Explanation:

Check below for program code.

#include <iostream>

#include <string>

#include <vector>

using namespace std;

class Song

{

public:

void SetNameAndDuration(string songName, int songDuration)

{

name = songName;

duration = songDuration;

}

void PrintSong() const

{

cout << name << " - " << duration << endl;

}

string GetName() const { return name; }

int GetDuration() const { return duration; }

private:

string name;

int duration;

};

class Album

{

public:

void SetName(string albumName) { name = albumName; }

void InputSongs();

void PrintName() const { cout << name << endl; }

void PrintSongsShorterThan(int songDuration) const;

private:

string name;

vector<Song> albumSongs;

};

void Album::InputSongs()

{

Song currSong;

string currName;

int currDuration;

cin >> currName;

while (currName != "quit")

{

cin >> currDuration;

currSong.SetNameAndDuration(currName, currDuration);

albumSongs.push_back(currSong);

cin >> currName;

}

}

void Album::PrintSongsShorterThan(int songDuration) const

{

unsigned int i;

Song currSong;

cout << "Songs shorter than " << songDuration << " seconds:" << endl;

/* Your code goes here */

for(int i=0; i<albumSongs.size(); i++){

currSong = albumSongs.at(i);

if(currSong.GetDuration()<songDuration){

currSong.PrintSong();

}

}

}

int main()

{

Album musicAlbum;

string albumName;

getline(cin, albumName);

musicAlbum.SetName(albumName);

musicAlbum.InputSongs();

musicAlbum.PrintName();

musicAlbum.PrintSongsShorterThan(210);

return 0;

}

4 0
3 years ago
Which of the following is not an algorithm?
Kipish [7]

Answer:

The correct answer is: "D. shapoo instructions (lather, rinse, repeat)".

Explanation:

Among the options given, letter D is the only one which does not apply and  may not function as an algorithm. An algorithm is a set of rules and/or instructions which aims at solving a problem and/or task, therefore, "shapoo instructions" do not classify as an algorithm because they are only written informations to explain how to use a product (lather, rinse, repeat), rather than setting a procedure for solving a problem in terms of technology tools. All the other options are examples of algorithms because they already exist as such and also function as technology tools.

(ps: mark as brainliest, please?!)

7 0
3 years ago
Write a function solution that given an array a of n integers (between -100 and 100), returns the sign (-1,0,1) of product of al
JulijaS [17]

left[0]=a[0];

for(int i=1;i<=n-1;i++)

   left[i]=(left[i-1]*a[i])%M;

right[n-1]=a[n-1];

for(int i=n-2;i>=0;i--)

   right[i]=(right[i-1]*a[i])%M;

for query q

   if(q==0)

       return right[1]%M;

   if(q==n-1)

       return left[n-2]%M;

   return (left[q-1]*right[q+1])%M;

4 0
2 years ago
Which of the following accurately describe the
Ronch [10]

Answer:

I can get a few months ago but the other use of the way you can you are you have a few weeks ago

3 0
2 years ago
Read 2 more answers
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