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Nataly_w [17]
3 years ago
6

What could have made you redesign your plan? Select 3 options.

Computers and Technology
1 answer:
Masteriza [31]3 years ago
5 0

Answer:

so that their username will still be used and so the can renember the username

Explanation:

that is why

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A _____ is relatively inexpensive to install and is well-suited to workgroups and users who are not anchored to a specific desk
KengaRu [80]

Answer:

B) wireless local area network (WLAN)

Explanation:

WLAN which fully meaning is WIRELESS LOCAL AREA NETWORK is a network provider that enables two or more mobile phone user , desktop or computer user to connect and have access to the internet by simply connecting to the local area wireless network and this type of wireless network are more cheaper to install.

Example of where WIRELESS LOCAL AREA NETWORK can be found are : School building, Office building, School campus, home, among others.

4 0
3 years ago
A goal should be___.
Luda [366]

Answer:

D

Explanation:

5 0
3 years ago
Read 2 more answers
Hello again, just need help debugging-I honestly have no idea how the "isSpace" etc methods work and I've tried various syntaxes
Julli [10]

import java.util.Scanner;

public class JavaApplication81 {

   

   public static void main(String[] args) {

       Scanner s = new Scanner(System.in);

       System.out.println("Input the string");

       String as = s.nextLine();

       int cons = 0;

       int a = 0;

       int e = 0;

       int i = 0;

       int o = 0;

       int u = 0;

       int space = 0;

       int punc = 0;

       char c;

       int misc = 0;

       String punctuation = ".!,?";

       String consonants = "bcdfghjklmnpqrstvwxyz";

       for (int k = 0; k < as.length(); k++){

           c = as.charAt(k);

       if (Character.isWhitespace(c)){

           space ++;

       }

       else if (punctuation.indexOf(c) != -1){

           punc++;

       }

       else if (consonants.indexOf(c) != -1){

           cons++;

       }

       else if (c == 'a'){

           a++;

       }

       else if(c == 'e'){

           e++;

       }

       else if (c == 'i'){

           i++;

       }

       else if (c == 'o'){

           o++;

       }

       else if (c == 'u'){

           u++;

       }

       else{

           misc++;

       }

       

   }

       System.out.println(a+" a's");

       System.out.println(e+" e's");

       System.out.println(i+" i's");

       System.out.println(o+" o's");

       System.out.println(u+" u's");

       System.out.println(space+" spaces");

   

       System.out.println(punc+" punctuations");

       System.out.println(cons+" consonants");

       System.out.println(misc+" misc. (uppercase vowels, etc.");

   }

   

}

This is one example of how it could be done.

5 0
3 years ago
Anyone know how to fix this
gizmo_the_mogwai [7]

Put the mouse at the top of the black part and click and hold down, and then drag it down to the bottom. And don't feel embarrassed to ask somebody lol

3 0
3 years ago
What term is used to describe the average amount of time that will pass for a device before a failure is expected to occur?
sleet_krkn [62]
A mean is another word for average (kind of)
7 0
3 years ago
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