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nadezda [96]
3 years ago
13

How would you solve 4(y – 3y) – 19 = 32

Mathematics
1 answer:
Fittoniya [83]3 years ago
6 0

Answer:

<u>y = - 6.375</u>

Step-by-step explanation:

Step 1:

4 ( y - 3y ) - 19 = 32        Equation

Step 2:

4y - 12y - 19 = 32         Multiply

Step 3:

- 8y - 19 = 32         Combine Like Terms

Step 4:

- 8y = 51        Add 19 on both sides

Step 5:

y = 51 ÷ - 8         Divide

Answer:

<u>y = - 6.375</u>

Hope This Helps :)

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Answer:

The correct answer is d) the ratio of the change in y to the change in x along the line.

We can tell this by looking at the slope formula.

m (slope) = (y2 - y1)/(x2 - x1)

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Figure EFGH on the grid below represents a trapezoidal plate at its starting position on a rotating platform:
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Alexander is building a rectangular pen in his backyard for his dog. The pen will have a length of 13 feet and a width of 2x fee
faust18 [17]

Answer:

4x+26

Step-by-step explanation:

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3 years ago
PLEASE HELPP ♥
kirza4 [7]

Answer:

An exponential function is a function of the form

f(x)=bx

where b≠1 is a positive real number. The domain of an exponential function is (−∞,∞) and the range is (0,∞).

Solve the equation: 52x−3=752x−3=7.

Since we can’t easily rewrite both sides as exponentials with the same base, we’ll use logarithms instead. Above we said that logb(x)=ylogb⁡(x)=y means that by=xby=x. That statement means that each exponential equation has an equivalent logarithmic form and vice-versa. We’ll convert to a logarithmic equation and solve from there.

52x−3log

⎛⎝⎜

⎞⎠⎟=7=2x−352x−3=7log5

⁡(7

)=2x−3

From here, we can solve for xx directly.

2xx=log5(7)+3=log5(7)+32

A logarithmic function is a function defined as follows

logb(x)=ymeans thatby=xlogb⁡(x)=ymeans thatby=x

where b≠1b≠1 is a positive real number. The domain of a logarithmic function is (0,∞)(0,∞) and the range is (−∞,∞)(−∞,∞).

Solve the equation:

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With more than one logarithm, we’ll typically try to use the properties of logarithms to combine them into a single term.

log3(2x+1)log3(2x+1)+log3(x+2)log3((2x+1)(x+2))log3(2x2+5x+2)2x2+5x+22x2+5x−1=1−log3(x+2)=1=1=1=3=0log3⁡(2x+1)=1−log3⁡(x+2)log3⁡(2x+1)+log3⁡(x+2)=1log3⁡((2x+1)(x+2))=1log3⁡(2x2+5x+2)=12x2+5x+2=32x2+5x−1=0

Let’s use quadratic formula to solve this.

x=−5±52−4⋅2⋅−1−−−−−−−−−−−√2⋅2=−5±

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4.

What happens if we try to plug x=

4 0
3 years ago
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hammer [34]
One Method) Multiply 575 by .05 (5%=.05) then add the answer by 575
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