Point P is graphed at (4, 5) shown

Given the inequality -8 < 2, explain what happens when you multiply or divide both sides by 2 and what happens when you multi

Gnoma [55]

Answer:

The inequality sign remains same while multiply or divide both sides by positive numbers.

The inequality sign changes while multiply or divide both sides by negative numbers.

Step-by-step explanation:

The given inequality is - 8 < 2.

Now, if we multiply 2 in both sides then - 16 < 4

Again, if we divide by 2 into both sides then - 4 < 1

Therefore, the inequality sign remains the same while multiply or divide both sides by positive numbers.

Now, if we multiply -2 in both sides then 16 > -4

And, if we divide -2 into both sides then 4 > -1

Therefore, the inequality sign changes while multiply or divide both sides by negative numbers. (Answer)

3 0

3 years ago

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WHAT DO I DO WHEN I FAILED A ALGEBRA TEST

Delicious77 [7]

Answer:

Restudy and try to take it again.

Step-by-step explanation:

Try watching math videos and do extra studying on the areas you missed on your last attempt.

5 0

3 years ago

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Let P and Q be polynomials with positive coefficients. Consider the limit below. lim x→[infinity] P(x) Q(x) (a) Find the limit i

jenyasd209 [6]

Answer:

If the limit that you want to find is $\lim_{x\to \infty}\dfrac{P(x)}{Q(x)}$ then you can use the following proof.

Step-by-step explanation:

Let $P(x)=a_{n}x^{n}+a_{n-1}x^{n-1}+\cdots+a_{1}x+a_{0}$ and $Q(x)=b_{m}x^{m}+b_{m-1}x^{n-1}+\cdots+b_{1}x+b_{0}$ be the given polinomials. Then

$\dfrac{P(x)}{Q(x)}=\dfrac{x^{n}(a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n})}{x^{m}(b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m})}=x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}$

Observe that

$\lim_{x\to \infty}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\dfrac{a_{n}}{b_{m}}$

and

$\lim_{x\to \infty} x^{n-m}=\begin{cases}0& \text{if}\,\, nm\end{cases}$

Then

$\lim_{x\to \infty}=\lim_{x\to \infty}x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\begin{cases}0 & \text{if}\,\, nm \end{cases}$

3 0

3 years ago

Frank has four different credit cards, the balances and interest information of which are outlined in the table below. He would

Brums [2.3K]

Answer:

c. $467.29

Step-by-step explanation:

The total of balances is $9360. The payment can be computed using the amortization formula:

A = P(r/12)/(1 -(1 +r/12)^-n)

where A is the monthly payment, P is the principal (total balance), r is the annual rate, and n is the number of months.

Filling in your numbers, we have ...

A = $9360(0.18/12)/(1 -(1 +0.18/12)^-24) ≈ $467.29

Frank's monthly credit card payment will be $467.29.

6 0

4 years ago

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Lillian works 7hours each day for 5 days a week she earn £420 each week how much does she earn per hour

frosja888 [35]

Answer:

£12 per hour

Step-by-step explanation:

7 × 5 = 35 hours

35 h : 420

1 h : x

x = 420×1 / 35

= £12 per hour

8 0

4 years ago