The equation of a circle in general form is x2+y2+18x−36y+369=0

Mathematics

1 answer:

Rudiy273 years ago

8 0

(x+9)^2+(y-18)^2=36 is the equation in standard form. Hope this helps.~<span>Haяяison</span>

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Hey! Can someone check my answers?

Andrew [12]

The greatest common factor is the biggest number taken from the values.

Q1. The answer is <span>A. 5y^6
</span>
$20 y^{9} +5 y^{6}= 4*5 y^{9}+5 y^{6}$
Since $x^{a}* x^{b} =x^{a+b}$ , then $x^{9}= x^{3}* x^{6}$

Back to our expression:
$4*5 y^{9}+5 y^{6}=4*5 y^{3}*y^{6}+5 y^{6}=4 y^{3}*5y ^{6}+ 5y ^{6}*1=5 y^{6} (4y ^{3} +1)$
The greatest common factor is thus $5 y^{6}$

Q2. The answer is <span>D. 12xy^2
</span>
$12x y^{5}+60 x^{4} y^{2} -24 x^{3} y^{3}=12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}$
We will use the rule $x^{a}* x^{b} =x^{a+b}$ to factorise the exponents:
$12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}= \\ =12x*y^{2}*y^{3}+5*12*x* x^{3} *y^{2}-2*12x* x^{2} *y*y^{2}= \\ =12xy^{2}*y^{3}+12xy^{2}*5 x^{3} -12xy^{2}*2 x^{2} y= \\ =12xy^{2}(y^{3}+5 x^{3}-2 x^{2} y)$
The greatest common factor is thus $12xy^{2}$

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3 years ago

clayton uses 34 of a bottle of hot sauce for every batch of salsa he makes. yesterday, he used 214 bottles of hot sauce. how man

Aleks [24]

If he used 34 bottles for every batch just divide 214 bottles he used by 34 it takes for a batch
he made 6.3 batches

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3 years ago

one sixth of the students in a school marching band are in the percussion section, the percussion section has 6 students, how ma

Igoryamba

Answer:

36 students

Step-by-step explanation:

because if 1/6 is 6 students then you have to multiply the 6 by 6

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3 years ago

Read 2 more answers

Triangle ABC is shown on the graph. What are the coordinates of the image of point B after the triangle is rotated 270° about th

irina [24]

The coordinates of the image of point B after the triangle is rotated 270° about the origin is (4, 2)

<h3>How to determine the image of point B?</h3>

The complete question is added as an attachment

From the attached image, we have the following coordinate

B = (-2, 4)

When the triangle is rotated by 270 degrees, the rule of rotation is:

(x, y) ⇒ (y, -x)

For point B, we have:

B' = (4, 2)

Hence, the coordinates of the image of point B after the triangle is rotated 270° about the origin is (4, 2)

The equation of a circle in general form is ​ x2+y2+18x−36y+369=0 ​

The equation of a circle in general form is x2+y2+18x−36y+369=0