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Ivanshal [37]
3 years ago
15

What's the square root of 6.909877

Mathematics
2 answers:
Vesna [10]3 years ago
7 0
The answer is square root of 6.909877
I hope you like this answer, please Brainliest me, and have a good day! :D
Tanzania [10]3 years ago
4 0
The square root of 6.909877 is 2.628664489
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Please help me I will give brainliest
Rus_ich [418]

Answer:

60 milligrams

Step-by-step explanation:

just cross multiply! percentages are just fractions of 100. so you can say that \frac{45}{x} =\frac{75}{100}

multiple 75 by x and 45 by 100 and you get

4500=75x

divide both sides by 75 and you get 60

7 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
Burka [1]

Answer:  d) 0.9693

<u>Step-by-step explanation:</u>

refer to the z-table attached.  

The table shows the percent from the MEAN.  The percent below the mean is 50% so that needs to be added to the value in the table.  

Look on the left side for 1.8 and the top for 0.07 (which is 1.87).  

The value is 0.4693 --> add 0.5 to that value to get 0.9693.

6 0
3 years ago
PLEASE HELP ME!!  i have to answer this question fast please help
otez555 [7]
Y=-1/4x+7.5 is the right equation
5 0
3 years ago
Brady made a scale drawing of a rectangular swimming pool on a coordinate grid. The points (-20, 25), (30, 25), (30, -10) and (-
djverab [1.8K]

Answer:

Length = 50 units

width = 35 units

Step-by-step explanation:

Let A, B, C and D be the corner of the pools.

Given:

The points of the corners are.

A(x_{1}, y_{1}})=(-20, 25)

B(x_{2}, y_{2}})=(30, 25)

C(x_{3}, y_{3}})=(30, -10)

D(x_{4}, y_{4}})=(-20, -10)

We need to find the dimension of the pools.

Solution:

Using distance formula of the two points.

d(A,B)=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}----------(1)

For point AB

Substitute points A(30, 25) and B(30, 25) in above equation.

AB=\sqrt{(30-(-20))^{2}+(25-25)^{2}}

AB=\sqrt{(30+20)^{2}}

AB=\sqrt{(50)^{2}

AB = 50 units

Similarly for point BC

Substitute points B(-20, 25) and C(30, -10) in equation 1.

d(B,C)=\sqrt{(x_{3}-x_{2})^{2}+(y_{3}-y_{2})^{2}}

BC=\sqrt{(30-30)^{2}+((-10)-25)^{2}}

BC=\sqrt{(-35)^{2}}

BC = 35 units

Similarly for point DC

Substitute points D(-20, -10) and C(30, -10) in equation 1.

d(D,C)=\sqrt{(x_{3}-x_{4})^{2}+(y_{3}-y_{4})^{2}}

DC=\sqrt{(30-(-20))^{2}+(-10-(-10))^{2}}

DC=\sqrt{(30+20)^{2}}

DC=\sqrt{(50)^{2}}

DC = 50 units

Similarly for segment AD

Substitute points A(-20, 25) and D(-20, -10) in equation 1.

d(A,D)=\sqrt{(x_{4}-x_{1})^{2}+(y_{4}-y_{1})^{2}}

AD=\sqrt{(-20-(-20))^{2}+(-10-25)^{2}}

AD=\sqrt{(-20+20)^{2}+(-35)^{2}}

AD=\sqrt{(-35)^{2}}

AD = 35 units

Therefore, the dimension of the rectangular swimming pool are.

Length = 50 units

width = 35 units

7 0
3 years ago
In a calculus​ class, Jack Hartig scored 4 on a quiz for which the class mean and standard deviation were 2.9 and 2.1​, respecti
nataly862011 [7]

Answer: Norm Alpina did better with z-score 0.79

Step-by-step explanation:

Z score formula = (raw score - mean) / standard deviation

For Jack Hartig,

score = 4; mean = 2.9; standard deviation = 2.1

Hence, Z score = (4 - 2.9) /2.1

= 1.1/2.1

= 0.52

For Norm Alpina,

score = 8; mean = 6.5; standard deviation = 1.9

Hence, Z score = (8 - 6.5) /1.9

= 1.5/1.9

= 0.79

Relatively, Norm Alpina did better for having Z score 0.79

6 0
3 years ago
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