Answer:
693 fish
Step-by-step explanation:
In 10 years, we can tell that the amount of fish increased by 1.833...(990 divided by 540) times. If we divide 1.833... by 10, we can find how much the pond increases by yearly. we get 0.1833... If we multiply that by 7 (because the gap between 1986 and 1979 is 7 years), we get 1.2833... So, if we multiply 540 by 1.28333..., we get 693 fish.
It equals 7958.1. hope it helps
36=2*2*3*3=2²*3²
60=2*2*3*5=2²*3*5
LCM(36,60)=2*2*3*3*5=2²*3²*5=180
Answer:
The margin of error is given below:

Where:



Therefore, the option E = z*6% is correct as it closest to the given answer
Answer:
g(t) - h(t) = -2t - 1
Step-by-step explanation:
g(t) - h(t) = t-3-3t+2
= -2t -1